Yuto and lian are at train stations 1,880 kilometers apart. yuto boards a train heading east at an average

10 answers
Question:

Yuto and lian are at train stations 1,880 kilometers apart. yuto boards a train heading east at an average speed of 220 kilometers per hour. at the same time, lian boards a train heading west on a parallel track at an average speed of 250 kilometers per hour. how far has lian traveled when the two trains pass each other?
470 kilometers
880 kilometers
940 kilometers
1,000 kilometers

[tex]Yuto and lian are at train stations 1,880 kilometers apart. yuto boards a train heading east at an a[/tex]


Answers

For the answer to the question above, we'll have to use the formula for velocity which is v = d
                    t        and d = vt

Since the total distance is given, therefore we can get the time and it will look like this.

220t + 250t = 1880
470t = 1880
470      470
the problem indicates that the train runs 250kph
Let's substitute:

d = 250(4)

the distance traveled by Lian is 1000km

the distance traveled is 1,000

1,000 km

Step-by-step explanation:

Assume that when two train pass each other, Lian has traveled x (km)

=> The time Lian has traveled when two trains pass each other is:

Time = Distance/ Rate = x/ 250 (hour)

As Lian and Yuto travelled from the two opposite train stations and the train stations are 1,880 km apart

=> When two train pass each other, Yuto has traveled 1,880 - x (km)

=> The time Yuto has traveled when two trains pass each other is:

Time = Distance/ Rate = (1,880 - x)/220 (hour)

As Lian and Yuto board at the same time, so that when two trains pass each other, the time both of them have traveled is equal

=> x/ 250 = (1,880 - x)/220

=> 220x = 250 x (1,880 -x)

=> 220x = 470,000 - 250x

=> 470x = 470,000

=> x = 1,000

So that, when two train pass each other, Lian has traveled x = 1,000 km

170 km/h

Step-by-step explanation:

D.

Step-by-step explanation:

The answer is D. 1,000

The correct answer is: D. 1,000.

the correct answer is
D) 1000 kilometers                                                                              

Then distance traveled by Yuto to meeting point = 1,880 - D
Times taken by both to travel to meeting point are equal
Therefore, we get:  1880 - D/220 = D/250
250(1,880 – D) = 220D Cross-multiplying
470,000 – 250D = 220D
- 250D – 220D = - 470,000
- 470D = - 470,000
D, or distance Lian traveled = -470000/-470, or 1000 km

To solve this problem you must apply the proccedure shown below:
 1. You have that the distance traveled by Lian is "x" and the distance traveled by Yuto is 1880-x.

 2. You have that the formula for calculate the speed is:
 V=d/t

 V1=d1/t1
 250=x/t1

 V2=d2/t2
 220=1880-x/t2
 
 Where d is the distance and t is the time.

 3. The problem says that Lian and Yuto board the trains at the same time, therefore:
 t1=t2
 x/250=1880-x/220
 x=1000 km

 Therefore, the answer is: 1000 km.

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