# Y={x+3 if x 303-xifi2x ifx>3}Domain: Answer hereIncreasing: (0,0)U(3.c)Range: Answer hereDecreasing (1.3)**Qroepe(s):

###### Question:

Domain: Answer here

Increasing: (0,0)U(3.c)

Range: Answer here

Decreasing (1.3)

**Qroepe(s): Answer here

Positive: Answer here

intercept: Answer here

Negative Answer here

maximum: Answer here

***y → Answer here

mismum: Answer here

011) Answer here

## Answers

Increasing Vcc will increase the duty cycle

Explanation:

Pick the correct statement from the list below

Increasing Vcc will increase the duty cycle

Vcc is a common collectorVcc is a term in electronics depicting a voltage from a power supply connected to the collector. The reason the letter is doubled ''cc" is to denote the voltage from the ground to the collector.Increase in Vcc lowers the frequency and increase the duty cycle as the time takes longer to charge .-Increasing opportunity costs

-Increasing marginal costs

-Increase labor productivity

Explanation:

A supply curve is a graphical form of representation of the price of the product and the quantity of the product which the seller can supply in the market. The supply curve slopes towards upward. This represents that the higher price brings with it an increase in the high amount of profit. Also, there is a direct relationship among the quantity of the commodity and the price which he is willing to sell.

1. 1.72 moles of potassium.

2. All of the answers are true

3. Are used up during a reaction

Explanation:

Recall that the number of moles is obtained from;

Number of moles= Mass of potassium/ molar mass of potassium

Mass of potassium= 67 g

Molar mass of potassium= 39 gmol-1

Number of moles of K= 67 g/ 39 gmol-1

Number of moles = 1.72 moles of potassium.

2. When we look at all the options, we will realize that all the options are true. The rate of reaction doubles for each 10°C rise in temperature, increasing reactant concentration increases particle collision and ultimately increases the rate of reaction. Rate of reaction deals with rate of disappearance of reactants or rate of appearance of products.

3. Catalysts remain unchanged in a chemical reaction because they do not actually participate in the reaction. Hence they are not used up in any chemical reaction.

1. A reduction in market price will lead to an increase in quantity supplied

2. Diminishing marginal utility

3. Add up quantities supplied by all individual producers for each price

Explanation:

Increase; decreasing

Explanation:

Grants are specific amounts of money given to entities by government, individuals, organizations for a specific purpose in which the entity given the money doesn't pay back.

Loans are specific amounts of money, properties and the likes given to entities in exchange for future repayment in loan value along with interest.

When there are increases in the loan and grant for college expenses, there would be an increase in the number of graduates. But an increase in the number of graduates reduces the amount available for each graduate, thus decreasing wages paid to college graduates.

None of the other answers is correct.

Explanation:

Williams A. Phillips was a notable economist born in New Zealand. Phillips wrote a famous article titled "The Relation between Unemployment and the Rate of Change of Money Wage Rates in the United Kingdom, 1861-1957" published in 1958 by Economica. In the article, he used data for the United Kingdom (U.K) to illustrate on a graph, a negative or inverse relationship between the rate of change of employee wages in the U.K and the unemployment rate in the United Kingdom (U.K).

Consequently, using the Phillips curve it is practically impossible for policymakers to reduce both the inflation rate and the unemployment rate because as the inflation rate decreases; the unemployment rate increases and vice-versa.

However, according to the Phillips curve, policymakers can reduce inflation and increase unemployment if aggregate demand is contracted.

One of the factors people use when deciding where they will live is the availability of resources.

Resources are unevenly distributed throughout the world.

finding suitable landfill locations

decreased availability of renewable resources

increased reuse of resources

increased use of resources

to reduce habitat destruction

to decrease reliance on fossil fuels

coal

biomass

Overfishing= deplete the stock of fish in (a body of water) by too much fishing.

Environmental protection in North America will not affect Antarctica or Australia.

Environmental protection efforts today will affect people in the future.

Rural

pollution

expansion of deforestation

enforcement of environmental regulations

They expand urban development.

desalinization

conservation

green

global warming

invasive= something that feels too close or does not belong

too little rain

increased biodiversity

development

integrated resource management

positive population growth

oil spills

groundwater extraction

coastal development

leading

Explanation:

Step-by-step explanation:

Consider the function [tex]f(x) = 2x^3-15x^2[/tex] over the given interval.

a)Recall that the following derivatives' properties:

- [tex](x^n)' = n x^{n-1}[/tex]

-(f+g)' = f'+g' when f and g are differentiable

-(cf)' = cf', where c is a constant and f a differentiable function.

Then, using this properties we have that

[tex]f'(x) = 2\cdot 3 x^{2}- 15 \cdot 2 x = 6x^2-30x[/tex]

[tex]f''(x) = 6\cdot 2 x -30 = 12x-30[/tex]

b) Recall that a critical point of a function f is where it's derivatives are 0 or they don't exist. From point a we have that both f' and f'' are polynomials, so the derivatives are continous. Hence,the critical points are where the first derivative is equal to zero.

Then, we have the following equation

[tex]6x^2-30x = 0 = x(6x-30) = 6x(x-5)[/tex]

Hence, the only critical points are x=0 and x=5.

c) Recall that the inflection points are were f''(x) is zero. Then, we have the following equation

[tex]12x-30=0[/tex]

The solution of this equation is [tex]x=\frac{30}{12}= \frac{5}{2}=2.5[/tex]

so x=2.5 is an inflection point of the function f