X+6 What values make the inequality - <0 true? ० + -7-6 -5 -4 -3 -2 - 1 0 1 2 3 4 5 6 7 | ० +

8 answers
Question:

X+6
What values make the inequality -
<0 true?


+
-7-6 -5 -4 -3 -2 -
1
0
1
2
3
4
5 6
7 |

+
-7-6 -5 -4 -3 -2 -10 1 134567x
0
4
++
-7-6-5-4-3 -2 -10 1 2 3 4 5 6 7x


-7-6-5-4-3-2-101234567

Answers

456 divided by 100 is 4.56 So N=100

The monthly mortgage payment is $640

Step-by-step explanation:

The cost of the house is $159,000

The down payment made is 20%. This means that the amount paid as down payment is

20/100 × 159000 = 31800

The balance to be paid would be

159000 - 31800 = $127200

We would apply the periodic interest rate formula which is expressed as

P = a/[{(1+r)^n]-1}/{r(1+r)^n}]

Where

P represents the monthly payments.

a represents the amount of the loan

r represents the annual rate.

n represents number of monthly payments. Therefore

a = $127200

r = 0.044/12 = 0.0037

n = 12 × 30 = 360

Therefore,

P = 127200/[{(1+0.0037)^360]-1}/{0.0037(1+0.0037)^360}]

P = 127200/[{(1.0037)^360]-1}/{0.0037(1.0037)^360}]

P = 127200/{3.779 -1}/[0.0037(3.779)]

P = 127200/(2.779/0.0139823)

P = 127200/198.75127840198

P = $640

456÷100=4.56

How to check your work: 456÷4.56=100

7.32

Explanation:

swap rate is fixed rate that swap receiver requires for the paying the uncertain rate. SWAP rate is fixed interest rate that is required by Swap receiver in exchange of floating rate of LIBOR. Swap rate can be calculated by multiple formula using the spreadsheet. The formula listed below is the simplest version;

r = {1-d (0, 4)} / {∑4 d(0, t)}

= 1-d (0, 4) /4 T=1 d(0,t) = 0.0732

= 7.32

[tex]E = 4.37 \times 10^{-19} J[/tex]

Explanation:

As we know that the wavelength of the photon is given as

[tex]\lambda = 454 nm[/tex]

[tex]h = 6.626 \times 10^{-34} Js[/tex]

[tex]c = 2.998 \times 10^8 m/s[/tex]

now we have

[tex]E = \frac{hc}{\lambda}[/tex]

now plug in all data in it

[tex]E = \frac{(6.626 \times 10^{-34})(2.998 \times 10^8)}{454 \times 10^{-9}}[/tex]

now we know that

[tex]E = 4.37 \times 10^{-19} J[/tex]

a) test statistic, [tex]t_{s} = -4.20[/tex]

b) P-value = 0.0001

c) It can be concluded from the hypothesis that the company's stock has a mean value that is not 7.52 million shares i.e. the mean stock has changed in recent years

Step-by-step explanation:

There are 40 trading days, therefore, sample size, n = 40

Calculate the Sample mean:

[tex]\bar x = \frac{\sum x}{n} \\\bar x = \frac{4.153 +4.6228 + ...+...+5.4563}{40}\\\bar x = 5.5945[/tex]

Get the null and alternative hypothesis:

Null hypothesis, [tex]H_{0} : \mu = 7.52[/tex]

Alternative hypothesis, [tex]H_{a} : \mu \neq 7.52[/tex]

Calculate the sample standard deviation:

[tex]SD = \sqrt{\frac{\sum (x - \bar x)^{2} }{n - 1} } \\SD = \sqrt{\frac{(4.1531-5.5945)^{2} + (4.6228-5.5945)^{2}+...+ (5.4563-5.5945)^{2}}{39} } \\SD = \sqrt{\frac{327.6161}{39} } \\SD = 2.8983[/tex]

a) Calculate the test statistic:

[tex]t_{s} = \frac{\bar{x} - \mu}{SD/\sqrt{n} } \\t_{s} = \frac{5.5945 -7.52}{2.8983/\sqrt{40} }\\t_{s} = -4.20[/tex]

b) Calculate the P-value

Getting the P-value using the excel function:

P-value = (=T.DIST.2T(|ts|, df))

P-value = (=T.DIST.2T(4.20, 39))

P-value = 0.0001

c) If the level of significance, [tex]\alpha = 0.05[/tex]

The P-value (0.0001) < α(0.05), the null hypothesis is rejected.

It can therefore be concluded from the hypothesis that the company's stock has a mean value that is not 7.52 million shares i.e. the mean stock has changed in recent years

the value of n is 100 because if you were to divide 456 by 100 you would get your answer of 4.56

I THINK IT`S 100
hope i helped pls put thanks

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