Write the equation in standard form. Then factor the left side of the equation.3x2 + 19x = 14A (3x
Question:
A (3x + 2)(x – 7) = 0
B (2x – 3)(x + 7) = 0
C (2x + 3)(x + 7) = 0
D (3x – 2)(x + 7) = 0
Answers
2x^2 = 28 - x in standard form is 2x^2 + x = 28
Factoring, we have:
x(2x + 1) = 28
3x^2+19x-14=0 Standard form
(3x-2)(x+7)=0 Factored
4x+7×=15 think thats the right answer
[tex]given \: equation - - - \\ 2 {x}^{2} + 7 x = 15 \\ \\ standard \: form - - - \\ 2 {x}^{2} + 7x - 15 = 0 \\ \\ factorising \: left \: side - - - \\ \\ = 2 {x}^{2} + 7x - 15 \\ \\ = 2 {x}^{2} + 10x - 3x - 15 \\ \\ = 2x(x + 5) - 3(x + 5) \\ \\ = (x + 5)(2x - 3)[/tex]
C. (2x – 3)(x + 5) = 0
Step-by-step explanation:
The equation in standard form should be 2x^2 + 7x - 15 = 0
Factored the expression is (2x - 3)(x + 5).
In order to find the factored portion, you must look for factors of the front number (2) to use in the front of the parenthesis and factors of the last number (-15) to go in the end.
When we use the ones that we have above, it distributes to the overall end result.
(2x - 3)(x + 5)
2x^2 - 3x + 10x - 15
2x^2 + 7x - 15
[tex]17. Write the equation in standard form. Then factor the left side of the equation. 2x2 + 7x = 15[/tex]
2x^2 + 7x - 15 = 0
Factors: (2x - 3)(x + 5)
Step-by-step explanation:
To write the equation in standard form rearrange to this form ax^2 + bx + c = 0. Rearrange the equation 2x^2 + 7x = 15 by subtracting 15 from both sides.
2x^2 + 7x - 15 = 0
The left side factors into (2x - 3)(x + 5) since it multiplies to 2x^2 - 3x + 10x - 15 = 2x^2 + 7x - 15.
2x² = 28 - x
2x²+x-28=0
2x²+8x-7x-28=0
2x(x+4)-7(x+4)=0
(x+4)(2x-7)=0
(2x-7)(x+4)=0
B.) (2x - 7)(x + 4) = 0
Standard form of the equation, [tex]3x^2+19x-14=0[/tex]
Factor of the equation is, [tex](x+7)(3x-2)=0[/tex]
Step-by-step explanation:
The standard form of the quadratic equation is given as
[tex]Ax^2+Bx+C = 0[/tex]
Given the equation:
[tex]3x^2+19x = 14[/tex]
Subtract 14 from both sides we have;
[tex]3x^2+19x-14=0[/tex]
⇒The standard form of the equation is, [tex]3x^2+19x-14=0[/tex]
Now, find the factor of the given equation:
[tex]3x^2+19x-14=0[/tex]
⇒[tex]3x^2+21x-2x-14=0[/tex]
⇒[tex]3x(x+7)-2(x+7) = 0[/tex]
⇒[tex](x+7)(3x-2)=0[/tex]
Therefore, the factor of the equation is, [tex](x+7)(3x-2)=0[/tex]
Answers to Write the equation in standard form. Then factor the left side of the equation. 2x^2 + 7x ...standard form is ax^2 + bx + c=0 2x^2 + ... (2x - 3)(x + 5) = 0
C (2x-3)(x+5). I just know. Please give me the brainliest