Write the balanced chemical equation for each of these reactions. include phases. when

12 answers
Question:

Write the balanced chemical equation for each of these reactions. include phases. when aqueous sodium hydroxide is added to a solution containing lead(ii) nitrate, a solid precipitate forms. however, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [pb(oh)4]2–(aq) complex ion.

Answers

The chemical equation is written below.

Explanation:

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

The chemical equation for the reaction of elemental boron and oxygen gas follows:

[tex]4B+3O_2\rightarrow 2B_2O_3[/tex]

By Stoichiometry of the reaction:

4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.

The chemical equation for the reaction of diboron trioxide and water follows:

[tex]B_2O_3+3H_2O\rightarrow 2H_3BO_3[/tex]

By Stoichiometry of the reaction:

1 mole of diboron trixoide reacts with 3 moles of water to produce 2 moles of boric acid.

Hence, the chemical equations are written above.

The chemical equation is written below.

Explanation:

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

The chemical equation for the reaction of elemental boron and oxygen gas follows:

[tex]4B+3O_2\rightarrow 2B_2O_3[/tex]

By Stoichiometry of the reaction:

4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.

The chemical equation for the reaction of diboron trioxide and water follows:

[tex]B_2O_3+3H_2O\rightarrow 2H_3BO_3[/tex]

By Stoichiometry of the reaction:

1 mole of diboron trixoide reacts with 3 moles of water to produce 2 moles of boric acid.

Hence, the chemical equations are written above.

a) a *5+5= 20

5a + 5 = 20

5a = 20 - 5

5a = 15

a = 15/5

a = 3

b) b/5 - 5 = 4

b/5 = 4 + 5

b/5 = 9

b =9*5

b = 45

a. 2Ag(s) + 1/2O₂(g) + H₂S(g) → Ag₂S(s) + H₂O (l)

Oxidizing agent: O

Reducing agent: Ag

b. Fe (s) + 3O₂  →   2Fe₂O₃ (s)

Oxidizing agent: O

Reducing agent: Fe

c. 6CO₂ (g) + 6H₂O (l) → C₆H₁₂O₆ (s)  + 6O₂ (g)

Oxidizing agent: C

Reducing agent: O

Explanation:

a. Silver reacts with S, which is in the air as H₂S

2Ag(s) + 1/2O₂(g) + H₂S(g) → Ag₂S(s) + H₂O (l)

Ag changes from 0 to +1, the oxidation state - Oxidation

O changes from 0 to -2, the oxidation state - Reduction

b. Iron reacts with O, from the air

Fe (s) + 3O₂  →   2Fe₂O₃ (s)

Fe changes from 0 to +3, the oxidation state - oxidation

O changes from 0 to -2, the oxidation state - Reduction

c. 6CO₂ + 6H₂O → C₆H₁₂O₆  + 6O₂

C changes from +4 to +1, the oxidation state - reduction

O changes from -2 to O, the oxidation state - oxidation

f(x - n) - translate the graph f(x) right n units

f(x + n) - translate the graph f(x) left n units

f(x) - n - translate the graph f(x) down n units

f(x) + n - translate the graph f(x) up n units

A) Translate the graph of y = x² right 3 units.

f(x - 3) = (x - 3)²

B) Translate the graph of y = |x| left 5 units.

f(x + 5) = |x + 5|

If you want to translate f(x) or down k units, it's f(x)+k. If you want to move it to the left k units it's f(x+k) so A is:

[tex]x^3+3[/tex]

and B is:

[tex](x+2)^2-3=x^2+4x+4-3=x^2+4x+1[/tex]

Step-by-step explanation:

a)    2/3 x+17>or equal to 29

2/3 x greater than or equal to 12

2x greater than or equal to 36

x greater than or equal to 18

b) x(7) - 25 < -39

7x < -14     (25-39)

x= -2

c) 10-3x<61

subtract 10 from both sides

-3x<51

divide by -3

x= -17

d) (x+9)/4  greater than or equal to -2

multiply both sides by 4

x+9 greater than or equal to -8

subtract 9 from both sides

x is greater than or equal to -17

e)  -5+1/2x <3

add 5 to both sides

1/2x <8

multiply both sides by 2

x<16

f)  2x-14 less than or equal to 50

add 14 to both sides

2x less than or equal to 64

divide both sides by 2

x less than or equal to 32

A)

Let the number we think be x.

Then,

According To The Question

=( x × 5 ) + 5 = 20
= x × 5 = 15
= x = 15/5 = 3

b)

Let the number we think be x.

Then,

According To The Question

=( x/5 ) - 5 = 4
= x/5 =9
= x = 9 × 5 = 45

HOPE THIS WILL HELP YOU

A: x=-4
B: y=2
C: n=4
Hope this helps!!!

It forms calcium phosphate and potassium nitrate
2 K3PO4 + 3Ca(NO3)2 --> Ca3(PO4)2 + 6KNO3

Ithink it is quantity of plants

The dispersed phase is liquid and dispersed medium in milk is liquid

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