WILL MARK YOU BRAINLEST IF YOU ANSWER CORRECTLY:Steven and Anna start running from the school. Steven
Question:
Answers
Step-by-step explanation:
An application of linear equations can be found in distance problems. When
solving distance problems we will use the relationship rt = d or rate (speed) times
time equals distance. For example, if a person were to travel 30 mph for 4 hours.
To find the total distance we would multiply rate times time or (30)(4) = 120.
This person travel a distance of 120 miles. The problems we will be solving here
will be a few more steps than described above. So to keep the information in the
problem organized we will use a table. An example of the basic structure of the
table is blow:
11.25 feet
Step-by-step explanation:
3*15=45;
45/4=11.25
An application of linear equations can be found in distance problems. When solving distance problems we will use the relationship rt = d or rate (speed) times time equals distance. For example, if a person were to travel 30 mph for 4 hours. To find the total distance we would multiply rate times time or (30)(4) = 120. This person travel a distance of 120 miles. The problems we will be solving here will be a few more steps than described above. So to keep the information in the problem organized we will use a table. The third column, distance, will always be filled in by multiplying the rate and time columns together. If we are given a total distance of both persons or trips we will put this information below the distance column. Two joggers start from opposite ends of an 8 mile course running towards each other. One jogger is running at a rate of 4 mph, and the other is running at a rate of 6 mph. After how long will the joggers meet? The basic table for the joggers, one and two. We are given the rates for each jogger. These are added to the table We only know they both start and end at the same time. We use the variable t for both times The distance column is filled in by multiplying rate by time. As the example illustrates, once the table is filled in, the equation to solve is very easy to find. This same process can be seen in the following example
Step-by-step explanation: Answers - Distance, Rate, and Time Problems
1) 1
1
3
2) 25 1
2
, 20 1
2
3) 3
4) 10
5) 30, 45
6) 3
7) 300
13
8) 10
9) 7
10) 30
11) 150
12) 360
13) 8
14) 10
15) 2
16) 3
17) 48
18) 600
19) 6
20) 120
21) 36
22) 2
23) 570
24) 24, 18
25) 300
26) 8, 16
27) 56
28) 95, 120
29) 180
30) 105, 130
31) 2:15 PM
32) 200
33) 1
3
34) 15
35) 27
4
36) 1
2
37) 3, 2
38) 90
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