# Which of these sets of ordered pairs satisfies an exponential equation? {(1,-1),(2,-4).3,-9),(4,-16)) {(1,-1),(2, -8),(3,-27),(4,

5 answers

###### Question:

Which of these sets of ordered pairs satisfies an exponential equation?

{(1,-1),(2,-4).3,-9),(4,-16))

{(1,-1),(2, -8),(3,-27),(4, -64))

(01.-2),(3,-8),(5,-32).(7.-128)}

((1.-2),(3,2).(5,0).(7,10))

{(1,-1),(2,-4).3,-9),(4,-16))

{(1,-1),(2, -8),(3,-27),(4, -64))

(01.-2),(3,-8),(5,-32).(7.-128)}

((1.-2),(3,2).(5,0).(7,10))

## Answers

No

Step-by-step explanation:

F(x) has two real roots, -2 and +1. Those are the only x-intercepts.

f(x) has 2 x-intercepts. hope this helps

No.

This is because the y value of 1 repeats itself, which never happens in an exponential function. This function is likely quadratic, which forms a parabola.

Yes, the ordered pairs match y = 10·4^(-x).

Yes.

For each increment of x, the y value is halved. This can be represented by the function f(x)= 0.5^x.

The initial value here is 1 because when x=0, y=1.

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