# Which of the following is an extraneous solution of square root -3x-2=x+2? a) x = –6 b) x = –1 c) x = 1 d) x = 6

4 answers

###### Question:

Which of the following is an extraneous solution of square root -3x-2=x+2?

a) x = –6

b) x = –1

c) x = 1

d) x = 6

a) x = –6

b) x = –1

c) x = 1

d) x = 6

## Answers

Hello,

Answer A (x=-6 is an extraneous solution)

√(-3x-2)=x+2

==>-3x-2>=0

==>x<= -2/3

So -3x-2=(x+2)²

==>-3x-2=x²+4x+4

==>x²+7x+6=0

==> (x=-6) or (x=-1)

if x=-6 then

√(-3*(-6)-2)=√16=4

-6+2=-4

False 4≠-4

if x=-1

√(-3*(-1)-2)=√1=1

-1+2=1

ok..

A) -6

Explanation:

I just took the pretest and got 100%

d. x = 6

Steps:

First, You square both sides to cancel the square root. Leaving -3x -2 on one side and 2x + 4 on the other.

Second, combine like terms. Subtract -2x both sides and add 2 both sides.

Third, that will give you 3x - 2x = 4 + 2. Which gives you x = 6.

A. x=-6

Step-by-step explanation:

i got it right on edge

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