# Which greek order is the most decorative? a. corinthian b. ionic c. doric

## Answers

Corinthian

Explanation:

Corinthian is the most decorative.

Corinthian is the most decorative

coordinates of r(b,c)

slope of nm is 0.

step-by-step explanation:

the midpoint of the line joining the points (x₁,y₁) and (x₂,y₂) is given by

[tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]

the midpoint of the line segment nk is given by

[tex](\frac{0+2b}{2},\frac{0+2c}{2})[/tex]

∴r(b,c)

the slope of the line joining the points (x₁,y₁) and (x₂,y₂) is given by

[tex]m =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

slope of rs is

[tex]m_{rs} =\frac{c-c}{a+d-b} = 0[/tex]

hence

coordinates of r(b,c)

and slope of nm is 0.

corinthian is the answer

Explanation:

plato

Corinthian order

Explanation:

The Corinthian order is the most ornate of the Greek orders, characterized by a slender fluted column having an ornate capital decorated with two rows of acanthus leaves and four scrolls. It is commonly regarded as the most elegant of the three orders.

the coordinates of r are (b,c)

the coordinates of s are (a+d,c)

the slopes of all the segments is 0

The most decorative one is Corinthian

Corinthian ionic doric

Corinthian is your answer

First it is Doric, then ionic, then Corinthian

Hope this helps

Corinthians were the most then Doric then Ionic