Which expression is equivalent to5y^3/(5y)^-2?o yoO 125y3012545

12 answers
Question:

Which expression is equivalent to
5y^3/(5y)^-2?
o yo
O 125y3
012545

Answers

[tex]\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{5y^3}{(5y)^{-2}}\implies 5y^3(5y)^2\implies 5y^3(5^2y^2)\implies 5\cdot 5^2\cdot y^3\cdot y^2
\\\\\\
5^{1+2}y^{3+2}\implies 5^3y^5\implies 125y^5[/tex]

5^3  y^5

125 y^5

Step-by-step explanation:

5y^3/(5y)^-2​

Distribute the exponent in the denominator

5y^3/(5 ^-2 y^-2)

A negative exponent in the denominator brings it to the numerator

5y^3 5 ^2 y^2​​

Combine like terms

5 * 5^2  * y^3 5^2

We know that a^b * a^c = a^(b+c)

5^(1+2) * y^( 3+2)

5^3  y^5

125 y^5

A) Y^5

Step-by-step explanation:

D.125y^5

Step-by-step explanation:

5y^3/(5y)^-2

= 5y^3 * (5y)^2

= 5^(1 + 2) * y^(3+2)

= 5^3 y^5

= 125y^5

I think the answer is D.

Step-by-step explanation:

[tex]\frac{ {5y}^{3} }{ {(5y)}^{ - 2} } \\ = \frac{ {5y}^{3} }{ {(\frac{1}{5y})}^{2} } \\ = {5y}^{3} \times {25y}^{2} \\ = 125 {y}^{5}[/tex]

its 125y⁵ on edge!!

Step-by-step explanation:

y^5

Step-by-step explanation:

The trick here is knowing that a negative power becomes positive when switching it's place from the denominator to the numerator.

[tex]\frac{5y^3}{5y^-2} = \frac{y^3}{y^-2} = \frac{y^3*y^2}{1} = y^5[/tex]

so the answer is y^5

It should be d 125^5

It’s a. I’m pretty sure that you keep the constants when you divide so it should be a. Please mark me brainliest

The answer to the question is 125y^5

24

step-by-step explanation:

question: use the following table of a school bus during morning pickups to calculate its average speed between 2.8 km and 4.2 km

answer: 42 km/h

explanation: 1.4/0.033 42.42424 = 42 km/h

question answered by

(jacemorris04)

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