# Which equation is equivalent to sq. root x^2 + 81 = x + 10

7 answers

## Answers

x² +81 = x² +20x +100

Step-by-step explanation:

Square both sides of the original equation:

(√(x² +81))² = (x +10)²

x² +81 = x² +20x +100

Option D is correct

[tex]x^2+81 = x62+20x+100[/tex]

Step-by-step explanation:

Given the equation:

[tex]\sqrt{x^2+81}=x+10[/tex]

Squaring both sides we get;

[tex]x^2+81 = (x+10)^2[/tex]

Using identity rule:

[tex](a+b)^2 = a^2+2ab+b^2[/tex]

then;

[tex]x^2+81 = x62+20x+100[/tex]

Therefore, [tex]x^2+81 = x62+20x+100[/tex] equation is equivalent to [tex]\sqrt{x^2+81}=x+10[/tex]

The answers D √x=15-11

D is the right answer

The answer is x= 214

idk

step-by-step explanation:

[tex]The vector 6,-5 is reflected across the y=x and the resulting matrix is dilated by a scale of -1.5[/tex]there is no graph so i cant sorry

step-by-step explanation:

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