When the valve between the two containers is opened and the gases allowed to mix, how does the volume

Missing question: 
Nitrogen: 2.0 L; 1.0 atm; 25°C.
Oxygen: 3.0 L; 2.0 atm; 25°C.
When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.

The volume occupied by the N₂ gas change : 5 L

Further explanation

There are several gas equations in various processes:

1. The ideal ideal gas equation PV = nRT

PV = NkT

N =number of gas particles

n = number of moles

R = gas constant (8,31.10 ^ 3 J / kmole K

k = Boltzmann constant (1,38.10 ^ -23)

n = = N / No

n = m / m

n = mole

No = Avogadro number (6.02.10 ^ 23)

m = mass

M = relative molecular mass

2. Avogadro's hypothesis

In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules

So it applies: the ratio of gas volume will be equal to the ratio of gas moles

V1: V2 = n1: n2 3. Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

p1.V1 = p2.V2 3. Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

V1 / T1 = V2 / T2 4. Gay Lussac's Law

When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature

P1 / T1 = P2 / T2 5. Law of Boyle-Gay-Lussac

Combined with Boyle's law and Gay Lussac's law

P1.V1 / T1 = P2.V2 / T2

P1 = initial gas pressure (N / m2 or Pa)

V1 = initial gas volume (m3)

P2 = gas end pressure

V2 = the final volume of gas

T1 = initial gas temperature (K)

T2 = gas end temperature

From the attached picture, it shows that if the stopvalve is opened then the two gas systems / containers will be interconnected (almost the same as the related vessel system). So that the total volume filled by the two gases (O₂ and N₂) becomes:

total volume = O₂ container volume + N₂ container volume

total volume = 3 L + 2 L

total volume = 5 L

Learn more

a description of Charles’s law

Charles's law

State Boyle's, Charles's, and Gay-Lussac's laws

Keywords: containers, valve, O₂, N₂, volume, gas

[tex]When the valve between the two containers is opened and the gases allowed to mix, how does the volum[/tex]

Unless the temperature changes OR there was a difference in pressure between n1 & n2, the volume of BOTH gasses will remain the same, always.