When a rubber is stretched during a tensile test, its elongation is initially proportional to the applied

I don’t feel like reading

Excel attached with the solution.

Step-by-step explanation:

Mean

[tex]\bar{x}=\frac{\sum x_{i}}{n}[/tex]

Standard deviation

[tex]sd=\sqrt{\frac{\sum (x_{i}-\bar{x})}{n-1}}[/tex]

Confidence interval

[tex]\bar{x} \pm z_{\alpha}*sd/\sqrt{n}[/tex]

The formulas used are in the Excel file attached.

see explaination

Explanation:

Program source code below:

def displayNumbers():

string = ""

num = 0

#first loop to control 5 rows

for i in range(5):

#second loop to control columns

for j in range(5):

str1 = str(num)

# str1.ljust(5) function to left justify output string

#appending number in resulting string

string = string + str1.ljust(5)

#updating num for next iteration

num = num + 1

#new line after each row to display pattern correctly

string = string + "\n"

return string

def pattern():

string = ""

num = 0

#first loop to control 1-4 rows

for i in range(5):

#In second loop to control 5 columns

for j in range(5):

str1 = str(num)

if num == 2:

num = num -2

else :

num = num + 1

# str1.ljust(5) function to left justify output string

string = string + str1.ljust(5)

# new line after each row to display pattern correctly

string = string + "\n"

return string

#Function calls

print('\033[4m')

print('\033[1m{}\033[0m'.format('Output 1:\n'))

print(displayNumbers())

print('\033[4m')

print('\u0332\033[1m{}\033[0m'.format('Output 2:\new'))

print(pattern())

See attachment for sample output and screenshot.

Nb: Always refer to screenshot if there is an indentation error.

what do you need I am confused..?

what is a question I was confused

X - 4 < 5

Let's add 4 to each side
x < 9

I can't graph it for you, but I can tell you that you would put a point at 8, and a line (with an arrow) extending to the left. This is because x could be any value less than 9.