What type of Angle Pair do these two angles make?Are they Supplementary or Congruent? What kind of angle pair do the angles (13x-19)

4 answers
Question:

What type of Angle Pair do these two angles make? Are they Supplementary or Congruent?
What kind of angle pair do the angles (13x-19) and (17y + 5) make?
Are the two angles Supplementary or Congruent?

[tex]What type of Angle Pair do these two angles make? Are they Supplementary or Congruent? What kind[/tex]


Answers

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

[tex]Will give brainiest which of the following equations represents a line that is parallel to the line[/tex]

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: [tex]\sqrt{\frac{ {72x}^{16} }{ {50x}^{{{36} }}}} = \frac{ { \sqrt{72}x}^{ {16}^{ (\frac{1}{2}) } } }{ { \sqrt{50} x}^ {{36}^{ (\frac{1}{2}) } }}[/tex]multiply exponents per exponent rules to get: [tex]\frac{ { \sqrt{72}x}^{8} }{ { \sqrt{50}x}^{18} }[/tex]remember you subtract exponents from the denominator and add exponents in the numerator so: [tex]\sqrt{ \frac{72}{ 50}} \times ( {x}^{(8 - 18) } ) = \sqrt{ \frac{36}{25} } \times ( {x}^{ - 10} )[/tex]simplify further: [tex]\frac{6}{5} {x}^{ - 10} = \frac{6}{5 {x}^{10} }[/tex]so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.
[tex]Plz hurrywhat is the simplified form of  ? assume  x  ≠ 0.[/tex]

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