What is the solution of 7/5 equal nine over x

geometric series converge the common ratio r has magnitude less than one.

[tex]|r| < 1[/tex]

which is equivalent to

[tex]-1 < r < 1[/tex]

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

[tex]s = \dfrac{a}{1 -r}[/tex]

where a is the first term.

[tex]s = \dfrac{100}{1 - 1/2} = 200[/tex]

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

[tex]|x| < \frac 1 2 \sqrt[3]{2}[/tex]

The answer is all about the number 4

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant

i dont know men

step-by-step explanation: