What is the polar form of the equation? x^2+(y+5)^2=25

x=√-y^2-10y

Step-by-step explanation:

step 1:add y^-2 to both sides

x^2+(y+5)^2=25

x^2+y^2+10y+25+-y^2=25+-y^2

x^2+10y+25=-y^2+25

Step 2:add -10y to both sides

x^2+10y+25-10y=-y^2+25+-10y

x^2+25=-y^2-10y+25

step 3:add -25 to both sides

x^2+25-25=y^2-10y+25-25

x^2=-y^2-10y

step 4:take square root

x=√−y^2−10y

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

[tex]y< -2x+4[/tex]

[tex]y< x+3[/tex]

[tex]x< 3[/tex]

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

answer: 80cm^2

step-by-step explanation: