What is the oxidation state of an individual sulfur atom in baso4?

5 answers
Question:

What is the oxidation state of an individual sulfur atom in baso4?

Answers

Is +3 and O2 is -2 so when combining something like S8 + O2 you ger sulfur dioxide (SOz) but when balanced it is S2O3

the oxidation state of an individual sulfur atom in SO₃⁻² is +4.

Explanation:

1) Fundamental considerations: There are important rules that you need to know to find the oxidation states of neutral compounds or ions.

In a neutral compound the sum of the oxidation states is equal to zero. In an ion, the sum of the oxidation states is equal to the overall ionic charge.Except in peroxides, oxygen (O) atoms bonded to other atoms have oxidation state -2.

Those are the relevant rules for this question.

2) Procedure:

The ion for which you have to fiind the oxidation state of an indivitual sulfur atom is SO₃⁻².Let x be the oxidation state of the sulfur (S) atom.Oxidation state of O = -2Total oxidation number for 3 atoms of O: 3 × (-2) = - 6Overall ionic charge of SO₃⁻²: - 2Sum of the oxidation states: x + (-6) = overal charge⇒ x + (-6) = -2Solve for x: x = - 2 + 6 = + 4

4) Conclusion: the oxidation state of an individual sulfur atom in SO₃⁻² is +4.

The oxidation state of single oxygen atom is -2 since it is more electronegative and like to gain electrons.

The sum of the oxidation states of each atom = charge of compound

Let’s say the oxidation state of Sulfur is x.

Hence,

      x +4 * (-2) = -2

      x – 8         = -2

                  x   = +6

The oxidation state of individual Sulfur atom is +6

The oxidation state  of  an  individual  sulfur  atom in BaSO4  = 6+


     Explanation


In  a molecule the oxidation number is the sum  of oxidation  numbers of  its constituent   atoms.

     for our case  it  is  the oxidation  number of BaSO4 = Ba + S  +O=0

Since the oxidation number of S is  is  unknown let  be represented   by  Y

   The  oxidation  state  of Ba= 2+   and O=2-

Therefore the  oxidation state of   Y  is calculates as  below

      =  2+   +y  + (4 x2-)=0

     = 2+  +  y +8- =0

   like terms together

       =Y +2  -8=0

       =y-6=0

      take  -6 to the  other side

    y= 6+

                                                     

This does not make any since to me

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