# What is the formula of potassium chloride?

## Answers

> (KCl) <

The formula of Potassium Chloride is KCl.

It is a neutral salt which is formed by the reaction of potassium hydroxide with hydrochloric acid. It has no effect in litmus paper because it is neutral in nature. It can be checked by the help of pH paper, it turns pH paper into green in colour which proves that it is neutral salt.

11. The formula for potassium oxide is K2O. The potassium ion has a charge of 1+ and the oxygen ion has a charge of 2-.

12. Formula of dihydrogen monoxide is, H2O.The first part of the name, "dihydrogen," implies the presence of two hydrogen atoms. The second part, "monoxide," implies the presence of one oxygen atom.

13. Sodium bromide chemical formula is NaBr Formula and structure: Sodium bromide chemical formula is NaBr and the molar mass is 102.89 g mol-1.

14. Magnesium dichloride

15. Iodine pentafluoride

if i can get brainliest that would be great

answer: k2s

explanation:

My solution

39.0983+126.90447=166.00277

x/166.002277=.06

x=9.96g

Explanation:

Potassium oxide is an ionic compound. The potassium has a charge of K+ and oxygen has a charge of O2−. We need 2 potassium ions to balance one oxide ion making the formula K2O.

Potassium hydroxide is an ionic compound. The potassium has a charge of K+ and hydroxide has a charge of OH−. We need 1 potassium ion to balance one hydroxide ion making the formula KOH.

K2O+ H2O→KOH

To balance the equation we place a coefficient of 2 in front of the potassium hydroxide.

K2O+H2O→2KOH

I hope this was helpful.

See explanation below

Explanation:

In order to calculate this, we need to use the following expression to get the concentration of the base:

MaVa = MbVb (1)

We already know the volume of NaOH used which is 13.4473 mL. We do not have the concentration of KHP, but we can use the moles. We have the mass of KHP which is 0.5053 g and the molecular formula. Let's calculate the molecular mass of KHP:

Atomic weights of the elements to be used:

K = 39.0983 g/mol; H = 1.0078 g/mol; C = 12.0107 g/mol; O = 15.999 g/mol

MM KHP = (1.0078*5) + (39.0983) + (8*12.0107) + (4*15.999) = 204.2189 g/mol

Now, let's calculate the mole of KHP:

moles = 0.5053 / 204.2189 = 0.00247 moles

With the moles, we also know that:

n = M*V (2)

Replacing in (1):

n = MbVb

Now, solving for Mb:

Mb = n/Vb (3)

Finally, replacing the data:

Mb = 0.00247 / (13.4473/1000)

Mb = 0.184 M

This would be the concentration of NaOH

The formula for potassium dihydrogen phosphate is KH2PO4.

It is also know as monopotassium phosphate.

Molecular mass is

(1×39)+(2×1)+(1×31)+(4×16)

=39+2+31+64= 136

Therefore the molecular mass is 136

The formula is Mg(ClO3 )2

[ Refer to the attachment ]

[tex]If the formula for potassium chlorate is kclo3 and the formula for magnesium fluoride is mgf2, then[/tex]

First we need to find the number of moles of both K and O reacted

K - 0.779 g / 39 g/mol

= 0.02 mol

the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g

O₂ moles = 0.638 g / 32 g/mol

= 0.02 mol

the number of both K and O₂ moles reacted are equal

therefore stoichiometry of K to O₂ reacted are 1:1

then the formula of potassium superoxide is KO₂