What is the equation of the line with a y-intercept of –3 and a slope of 2?

A) y=-2x-2

y/x=slope -4/2=-2 y-intercept=b=-2 (put in y=mx=b form)

B) y=15/4x-1 or y=3.75x-1

C) y=-0.6664x-3(I DONT THINK THIS ONE IS RIGHT CHECK IT FIRST)

Hi there! :)

y = 2x - 3

Step-by-step explanation:

The slope intercept equation looks like this : y = mx + b

Where "m" is the slope and "b" is the y-intercept.

Your y-intercept = -3 → SO, b = -3

Your slope = 2 → SO, m = 2

Replace the values of "b" and "m" in the equation, and you're done:

y = mx + b

y = 2x - 3

There you go! I really hope this helped, if there's anything just let me know! :)

how am i supposed to answer this?

So with intercepts, we know that one of the coordinates is 0 - that is because the line intercepts the axis at this point.

When we have a y-intercept of -3, it is written as (0,-3)

And when we have an x-intercept of -4.5, we write it as (-4.5,0)

So now we have our two points - let's find the slope using the equation:

[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] ---> [tex]\frac{0-(-3)}{-4.5-0}=\frac{3}{-4.5}[/tex]

If we convert -4.5 to an improper fraction, we get:

[tex]-4\frac{1}{2}=-\frac{9}{2}[/tex]

So then we go back and simplify:

[tex]\frac{3}{-\frac{9}{2}}=3*-\frac{2}{9} =\frac{-6}{9}=-\frac{2}{3}[/tex]

So now we have our slope: [tex]-\frac{2}{3}[/tex]. Then we can write the equation:

[tex]y=-\frac{2}{3}x+b[/tex]

Let's use the point (0,-3) to solve for b:

[tex]-3=-\frac{2}{3}(0)+b[/tex]

[tex]b=-3[/tex]

So now we can write the equation:

[tex]y=-\frac{2}{3} x-3[/tex]

This is the equation of the line with points (0,-3) and (-4.5,0).

Y=(2/3)x-2

Step-by-step explanation:

Y=2x-3

Step-by-step explanation:

What is the equation of the line with a y-intercept of -3 and a slope of 2?

y = 2x - 3