What is the equation of the circle with center (-3.2, 2.1,) and radius 4.3

[tex](x+3.2)^2+(y-2.1)^2=4.3^2[/tex]

[tex](x+3.2)^2+(y-2.1)^2=(4.3)^2[/tex]

Step-by-step explanation:

It is given that the center of the circle is (-3.2,2.1) and radius is 4.3.

Now, the equation of the circle with center (a,b) and the radius 'r' is represented as:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

Now, the given center is (-3.2,2.1) and radius is 4.3, thus the equation of the circle becomes,:

[tex](x-(-3.2))^2+(y-2.1)^2=(4.3)^2[/tex]

[tex](x+3.2)^2+(y-2.1)^2=(4.3)^2[/tex]

Which is the required equation.

If this makes sense lol... C = 2πr ≈ 2(3.14)(4.3) ≈ 27.02 m. An object travels in a circle of radius 4.3m at constant speed. It takes 1.4 seconds to go around once

The equation of this cercle is (x + 3.2)² + (y + 2.1)² = 4.3²

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.