What is an equation of the line that passes through the point (3, 3) and is parallel to the line 4x

10 answers
Question:

What is an equation of the line that passes through the point (3, 3) and is parallel to
the line 4x – 3y = 21?

Answers

y=6x

Step-by-step explanation:

The formula you use is y=mx+b you get 4x-3y=21 you add 3 to 3y and 21 then you cancel out the 3's 4x goes down and then you add 21+3 which equals 24 then you divide it all by 4 except y, you drop the y down and you should get y=6x

Hope you get it right

Y=6x because you have to subtract

  y = 0

Step-by-step explanation:

A line with a slope of zero is a horizontal line, having an equation of the form ...

  y = constant

Since the y-coordinate of the given point is 3, the constant must be 3.

  y = 3 . . . . horizontal line through (3, 3)

0x+3 or y=3

Step-by-step explanation:

If you need clarification use a graphing calculator like Desmos to check this

[tex]y = 5x - 12[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!!


[tex]Find the slope-intercept form of the equation of the line thatpasses through the point (3, 3) and ha[/tex]

[tex]y=-3[/tex]

Step-by-step explanation:

*Notice that they have the same [tex]"y"[/tex] value.

Hope this helps!!

all work is shown. see above


[tex]What is the equation of the line that passes through the point (3, -3) and has a slope of 0?[/tex]

Step-by-step explanation:

ghanami

Step-by-step explanation:

Hello : let  A(3,3)    B(6,-1)

the slope is :   (YB - YA)/(XB -XA)

(-1-3)/(6-3)  = -4/3

an equation is the line is : y = ax+b        a is a slope

y = (-4/3)x+b

but this line passes by (6;-1)

so : -1 = (-4/3)(6)+b

b = 7

the equation is : y = (-4/3)x+7

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

(x₁, y₁) - point on a line

We have the point (3, -3) and the slope m = -2. Substitute:

[tex]y-(-3)=-2(x-3)[/tex]

[tex]y+3=-2(x-3)[/tex]- point-slope form

Convert to the slope-intercept form (y = mx + b):

[tex]y+3=-2(x-3)[/tex]        use the distributtive property

[tex]y+3=-2x+(-2)(-3)[/tex]

[tex]y+3=-2x+6[/tex]      subtract 3 from both sides

[tex]y=-2x+3[/tex]- slope-intercept form

Convert to the standard form (Ax + By = C):

[tex]y=-2x+3[/tex]        add 2x to both sides

[tex]2x+y=3[/tex]- standard form

Convert to the general form (Ax + By + C = 0):

[tex]2x+y=3[/tex]      subtract 3 from both sides

[tex]2x+y-3=0[/tex]- general form

The equation of the line is y = x

Step-by-step explanation:

To find the equation of this line, we first need to find the slope. To do that, we use the slope equation.

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - -3)/(3 - -3)

m = (3 + 3)/(3 + 3)

m = 6/6

m = 1

Now that we have the slope, we can use it and either point in point-slope form and solve for the equation.

y - y1 = m(x - x1)

y - 3 = 1(x - 3)

y - 3 = x - 3

y = x

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