What is 11- 9 1/4 simplfy
Answers
1 and 3/4 is the answer!
Hope this helps! May I have brainliest? :D
1. A
2.b
3.c
4.b
5.b
6.d
7.a
8.a
9.a
10.a
11.c
12.b
13.-6
14.-7/20
15.-3
I tried my best sorry if some are wrong hope you get a good grade (:
A. The tree increased in height each month during the entire 11-month period.
Step-by-step explanation:
A
Step-by-step explanation:
Divergers
Step-by-step explanation:
on edge
Step-by-step explanation:
The tree increased in height each month until the time period between month 9 and month 11
Step-by-step explanation: 1) ∫ 1/( x - 2)∧3/2 dx, Limits ⇒ infinite to 3
∫( x - 2)∧-3/2 = -2/( x - 2)∧1/2 + c
Limit⇒ infinite to 3: -2/(3 - 2) = -2 ( convergent)
2) ∫1/( 3 - 4x) dx, Limits⇒ 0 to infinite
Let u = 3 - 4x
du = -4 dx
∴ dx = -1/4du
Hence, -1/4∫1/udu = - 1/4ln u + c = -1/4ln(3 - 4x) + c
Limits⇒ 0 to infinite: -1/4㏑(3 - 0) = -1/4 ㏒3 (convergent)
3) ∫e∧(-5x)dx, Limits⇒ infinite to 2
Let u = -5x
du = -5dx
∴ dx = -1/5du
-1/5∫e∧-u = -1/5e∧-5x + c
Limits⇒ infinite to 2: -1/5e∧-5(2) = -1/5e∧-10 (divergent)
4) ∫x²/√(1 + x³)dx, Limits⇒ infinite to 0
Let u = 1 + x³
du = 3x²dx
∴ dx = 1/3x²du
1/3x²∫x²/u∧1/2du = 1/3㏑u∧1/2 + c = 1/3㏑(√1 + x²) + c
Limits⇒infinite to 0: 1/3㏒0 = infinite (divergent)
5)
6)∫1/(x² + x)dx, Limits⇒ infinite to 1
㏑(x² + x) + c
Limits⇒ infinite to 1: ㏒(1 + 1) = ㏒ 2 (divergent)
7) ∫3/x∧5dx = ∫3x∧-5dx, Limits⇒ (1 to 0)
- 3/4x∧-4 + c
Limits ( 1 to 0): -3/4(1)∧-4 - (-3/4(0)) = -3/4 + 0 = -3/4 (convergent)
8)∫1/(x + 2)∧1/4 dx, Limits (14 to -2)
Let u = x + 2
du = dx
∫1/u∧1/4 du = ∫u∧-1/4
3/4u∧3/4 = 3(x + 2)∧3/4/4 + c
Limits (14 to -2): 3(14 + 2)∧3/4/4 - (3(-2 + 2)∧3/4/4) = 3(16)∧3/4/4 - 0
3(2)³/4 = 3 X 8/4 = 3 X 2 = 6 (convergent)
9) ∫1/(x - 1)∧1/3dx, Limits (9 to 0)
Let u = x - 1
du = dx
∫1/u∧1/3 du = ∫u∧-1/3du = 2u∧2/3/3 + c = 2(x - 1)∧2/3/3 + c
Limits (9 to 0): 2(9 -1)∧2/3/3 - 2(0 - 1)∧2/3/3 = 2(8)∧2/3 - 2(-1)∧2/3/3
2(2)²/3 - 2/3 = 8/3 - 2/3 = 6/3 = 2(convergent)
10) ∫e∧x/(e∧x - 1), Limits (1 to -1)
Let u = e∧x - 1
du = e∧x dx
∴ dx = 1/e∧x du
1/e∧x∫e∧x/u du
∫1/u = ㏑u du + c = ㏒(e∧x - 1) + c
Limits (1 to -1): ㏒(e - 1) - ㏒e∧-1 - 1
㏒(e - e∧-1) (divergent)
11) ∫z∧2㏑z dz, Limits (2 to 0) (divergent)
12) Diververgent
Step-by-step explanation:
Patterns in Multiplication 75 ... 13. 1 __. 5 of 60 = 11. 1 __. 9 of 81 = 14. 1 __. 8. ⋅ 16 = 3. 10. 7. 9. 8. 12. 2. 10. 5 ... zeros in the product for the expression 600 ⋅ 500. 4-2. 1. 5__. 8. 5__. 7. 4. ... 15. 5,000. ×. 2. __. 18. 600. ×. 4. __. 7. 5__. 6. ⋅ 36 = 10. 2 __. 3. ⋅ 33 = 8. ... Solve the first problem with Place Value Sections.
Step-by-step explanation:
3. The tree increased in height each month until the time period between month 9 and month 11.
Step-by-step explanation:
We have been given a table that shows the height of the tree that Margo planted over an 11-month period.
Let us see which of the given statement can be supported by the information in the table.
1. The tree increased in height each month during the entire 11-month period.
We can see from our table of data that Margo's tree increased till 9 months and its height decreased between 9 to 11 months from 3 feet to 1.8 feet, therefore, first statement is not true.
2. The tree decreased in height each month during the entire 11-month period.
We can see from our table that height of Margo's tree increased till 9 months from 1.4 feet to 3 feet and its height decreased between 9 to 11 months from 3 feet to 1.8 feet, therefore, second statement is not true.
3. The tree increased in height each month until the time period between month 9 and month 11.
We can see that height of tree increased for 9 months (1.4 ft to 3 ft) and between 9 to 11 months height decreased (3 ft to 1.8 ft), therefore, our 3rd statement is true and the information given in the table is supporting this statement.
4. The tree decreased in height each month until the time period between month 9 and month 11.
We have seen that the tree increased in height each month until the time period between month 9 and month 11, therefore, our 4th statement is not true.
i hope this helps
Omg I can’t do this and will never get brainliest