Two sides and three vertices of an isosceles trapezoid are shown below. The fourth vertex is in the first quadrant. Draw the remaining
Question:
[tex]Two sides and three vertices of an isosceles trapezoid are shown below. The fourth vertex is in the[/tex]
Answers
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we have three similar triangles, because each has a right angle and shares an angle. let's write the angles in order: opposite to short leg, long leg, hypotenuse.
cab similar to bad similar to cbd
or as ratios,
ca: ab: cb = ba: ad: bd = cb: bd: cd
we also know
ac = ad + cd
(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd
(ad+cd)/cb=cb/cd
we have cb=6, ad=5 and seek x=cd.
[tex](5 + x)/6 = 6/x[/tex]
[tex]x(x+5) = 36[/tex]
[tex]x^2 +5x - 36 = 0[/tex]
[tex](x+9)(x-4) = 0[/tex]
we reject the negative root and conclude x=4
answer: 4
[tex]If bc = 6 and ad = 5, find dc. a) 4 b) 4.5 c) 7.2[/tex]none.
step-by-step explanation:
m
1
=
5
m1=5
b
=
−
1
b=-1
find the slope and y-intercept of the second equation.
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m
2
=
0
m2=0
b
=
−
6
b=-6
compare the slopes
m
m of the two equations.
m
1
=
5
,
m
2
=
0
m1=5,m2=0
compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.
m
1
=
5
,
m
2
=
0
m1=5,m2=0
g(x) = 3*(8(3^(x−2))+2)
g(x) = 24 (3^(x-2) )+6
the factor is 2
step-by-step explanation:
let f(x)=8(3^(x−2)+2)
to stretch a graph by 3, it would be 3f(x)
g(x) =3f(x)
g(x) = 3*(8(3^(x−2))+2)
g(x) = 24 (3^(x-2) )+6
x −2 0 2 4 6
f(x) 1/64 1/16 1/4 1 4
1/64 * z * z = 1/16
i multiplies by z twice because it its 2 steps from -2 to 0
1/64 z^2 = 1/16
multiply by 64 to clear the fraction on the left side
1/4 * 64 z^2 =1/16 *64
z^2 = 4
take the square root of each side
sqrt(z^2) = ±sqrt(4)
z = ±2
we are multiplying by 2 each time.