Tturns out the engineers designing the loop-the-loop didn’t really know physics – when they made

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Tturns out the engineers designing the loop-the-loop didn’t really know physics – when they made the ride, the first drop was only as high as the top of the loop-the-loop. to account for the mistake, they decided to give the mass an initial velocity right at the beginning. how fast do they need to push the mass at the beginning (now at a height equal to the top of the loop-the-loop) to get the mass around the loop-the-loop without falling off the track

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t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

c.the charges if the proton and electron and gravity

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Scissors and a seesaw both cut things that’s the only comparison

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