This Question: 1 pt 3 of 10 (1 complete) TIS QUI. TU PIS POS Lab Mat Courses A rectangular field is five times as long as it

The dimensions of fields are length = 264 yards and width = 66 yards

Solution:

Given that rectangular field is five times as long as it is wide and perimeter of field is 660 yards

Let "L" be the length of rectangular field

Let "W" be the width of rectangular field

From given information,

Length = 4 times the width

[tex]L = 4 \times W[/tex]

L = 4W

The perimeter of rectangle is given as:

perimeter of rectangle = 2(length + width)

Substituting the given values in above formula,

660 = 2(4W + W)

330 = 5W

Then length is given as: L = 4W

L = 4(66) = 264

Thus the dimensions of fields are length = 264 yards and width = 66 yards

Width = 20 yards , length = 100 yards.

Step-by-step explanation:

Let the field be x yards wide then it's length is 5x yards.

so x + x + 5x + 5x = 240

12x = 240

x = 20.

width = 20 , length = 100 yards.

Width = 20yards

Length = 100 yards

Step-by-step explanation:

The field is 5 times as long as it's widths...

Let's represent the width be with "w"

The length will then become *5 * w*

The perimeter of the Rectangular field then becomes:

Perimeter (P) = 2 ( w + l)

P = 2 ( w + 5w)

But P = 240

240 = 2w + 10w

240 = 12w

Divide through by 12

w = 240/12

w = 20 yards

That is ,the width = 20yards

The length is 5 times the width

Length = 5*w

Length = 5*20

Length = 100 yards

Width = 20yards

Length = 100 yards