There were 28,000 people at a ball game in los angeles. the day's receipts were $154,000. how many people
3 answers
Question:
There were 28,000 people at a ball game in los angeles. the day's receipts were $154,000.
how many people paid $11 for reserved seats and how many paid $4 for general
admission?
how many people paid $11 for reserved seats and how many paid $4 for general
admission?
Answers
There were 6,000 reserved seats and 22,000 general admission seats.
Step-by-step explanation:
Using the information given, we can create a system of equations.
X will represent the reserved seats and Y will represent the general admission seats.
x+y=28000
11x+4y=154000
The first equations is how many people are attending and the second question is the amount of money gained. We want to make the equations equal by doing the following:
x+y=28000
y=28000-x
By subtracting x from both sides, we have an equation equal to y, which we can plug in.
11x+4(28000-x)=154000
11x+112000-4x=154000
7x=42000
x=6000
We now have the amount of reserved seats, which we can plug into the frist equation.
6000+y=28000
y=22000
answer: 4 meters
step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.
hope this .
r = 78539458390583095803458309458039485093485 or just 3
step-by-step explanation:
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