The wheels of an automobile are locked as it slides to a stop from an initial speed of 30.0 m/s. if

3 answers
Question:

The wheels of an automobile are locked as it slides to a stop from an initial speed of 30.0 m/s. if the coefficient of kinetic friction is 0.600 and the road is horizontal, approximately how long does it take the car to stop?

Answers

  x = 76.5 m

Explanation:

Let's use Newton's second law at the point of contact between the wheel and the floor.

     fr = m a

     fr = miy N

     N-W = 0

     N = W

     μ mg = m a

     a = miu g

    a = 0.600 9.8

    a = 5.88 m / s²

Having the acceleration we can use the kinematic relationships to find the distance

     [tex]v_{f}[/tex]² = v₀² + 2 a x

    [tex]v_{f}[/tex] = 0

    x = -v₀² / 2 a

Acceleration opposes the movement by which negative

   x = - 30²/2 (-5.88)

   x = 76.5 m

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

Earthplanet yplanet y5=earth     *many different equationsplanet x1.5=earthplanet x is two times planet yobject 5,2500 mass5,1,3,2,4object 1 is four times obect 4

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