The slope of the line containing the points (-5, 3) and (-2, 1) is A. -2/3 B. 2/3 C. -3/2

7 answers
Question:

The slope of the line containing the points (-5, 3) and (-2, 1) is
A. -2/3
B. 2/3
C. -3/2

Answers

A.-2/3

Step-by-step explanation:

formula of gradient

dy/dx=y2-y2/x2-x1

1-3/-2-(-5)

=-2/3.

-2/3 is 100% right answer

The answer is -3/2

Slope = (y2 - y1)/(x2 - x1) = (1 - 3)/(-2 - (-5)) = -2/(-2 + 5) = -2/3

For perpendicular lines, m2 = -1/m1 = -1/(3/8) = -8/3

A line passing through point (-4, 0) and parallel to the y-axis is x = -4

[tex]diameter=\sqrt{(7-1)^2+(5+3)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10[/tex]
radius = diameter/2 = 10/2 = 5
center of circle = midpoint of diameter = ((-3 + 5)/2, (1 + 7)/2) = (2/2, 8/2) = (1, 4)
Required equation is (x - 1)^2 + (y - 4)^2 = 5^2
(x - 1)^2 + (y - 4)^2 = 25

That would be -2/3 because when you set it up on you have to find how much the X changes so going from -5 to -2 is adding 3 and going from 3 to 1 is subtracting to now just put those in a fraction make sure it is Y over X so that would be -2/3

The answer is C. Hope this helps: D

Yup. -2/3 is the answer.

In math we generally let “m” represent slope. So slope = m.

m = (rise / run) = [ (y2-y1) / ( x2-x1) ]

= (1 - 3) / (-2/-5) = (-2) / (3) = -2/3

= -2/3 is the answer !

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