The ratio of the lengths of the sides of a triangle abc is 3: 4: 6. m, n, and k are the

4 answers
Question:

The ratio of the lengths of the sides of a triangle abc is 3: 4: 6. m, n, and k are the midpoints of the sides. perimeter of the △mnk equals 5.2 in. find the length of the sides of the △abc. no picture.

Answers

Given that in a trianlgle the sides AB, BC, CA are in the ratio 3:4:6.

Let AB = 3k, BC = 4k and CA = 6k.

Then perimeter =3k+4k+6k = 13k

M, N, K are mid points of the sides.

By mid point theorem MN = 3k/2, NK = 4k/2 and KM = 6k/2

Hence perimeter of MNK = 13k/2 =5.2 (given)

Solve for k

k=2(5.2)/13 = 0.8

Hence sides are

AB = 3k = 3(0.8) = 2.4 in

BC = 4k= 3.2 in

CA = 4.8 in

Each midsegment is half the length of its corresponding parallel segment, so the perimeter of ∆MNK is half the perimeter of ∆ABC. Then the perimeter of ∆ABC is ...

... 2 × 5.2 in = 10.4 in

The side length ratios total 3+4+6 = 13 "ratio units" (corresponding to the total of side lengths, the perimeter), so the sides are 3/13, 4/13, and 6/13 of the perimeter, respectively. That is, the side lengths are ...

... 3/13 × 10.4 in = 2.4 in

... 4/13 × 10.4 in = 3.2 in

... 6/13 × 10.4 in = 4.8 in

(1/x + 1)^2 + 6 (1/x + 1) +5

6.5

step-by-step explanation:

you said it was in the question

~courtney

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