The manganese(II)-catalyzed redox reaction between cerium(IV) and thallium(I) is thought to proceed by a three-step mechanism:Ce4+(aq)

4 answers
Question:

The manganese(II)-catalyzed redox reaction between cerium(IV) and thallium(I) is thought to proceed by a three-step mechanism: Ce4+(aq) + Mn2+(aq) --> Ce3+(aq) + Mn3+(aq) (slow)
Ce4+(aq) + Mn3+(aq) --> Ce3+(aq) + Mn4+(aq)
Mn4+(aq) + Tl+(aq) --> Mn2+(aq) + Tl3+(aq)
a. If the first step of this mechanism is rate-determining (slow), choose the correct rate law for the overall process.
1. Rate = k [Ce4+]2
2. Rate = k [Ce4+] [Tl+]
3. Rate = k [Mn2+] [Mn3+]
4. Rate = k [Mn2+] [Ce4+]
5. Rate = k [Mn3+] [Tl+]
6. Rate = k [Ce4+]2 [Tl+]
b. Choose the correct chemical equation for the overall process.
1. Ce4+(aq) + Mn2+(aq) --> Ce3+(aq) + Mn3+(aq)
2. Ce4+(aq) + Mn3+(aq) --> Ce3+(aq) + Mn4+(aq)
3. 2Ce4+(aq) + Tl+(aq) --> 2 Ce3+(aq) + Tl3+(aq)

Answers

Given the yield is 98%

The reaction is

8H2S(g)+4O2(g)→ S8(l)+8H2O(g)

As per balanced equation eight moles of H2S will react with four moles of O2 to give one mole of S8

Let us calculate the moles of each reactant from given masses

30.0 grams of h2s

Moles = Mass / Molar mass = 30 / 34 = 0.88 moles

They need 0.44 moles of O2 to react

As 50.0 grams of o2  are given so

Moles = Mass / Molar mass = 50 / 16 = 3.125 moles

Thus H2S is the limiting reagent

8 moles of H2S will give one mole of S8

So 0.88 moles of H2S will give = 1 X 0.88 / 8 moles of S8 = 0.11 moles

However the yield is 98% so the actual moles of S8 formed = 0.98 X 0.11 = 0.1078 moles of S8

Mass of S8 produced = Moles X molar mass = 0.1078 X 256

= 27.6 grams of S8

Explanation:

Glucose and a plants and ur welcome

THE OVERALL UNBALANCED:
C6H12O2 + O2 -> CO2 + H2O + ENERGY

THE BALANCED:
C6H12O6 + 6O2 -> 6CO2 + 6H2O + ENERGY

IN WORDS IT WOULD BE:
Glucose + oxygen -> carbon dioxide + water + energy

a) Rate = k [Mn2+] [Ce4+]

b) 2Ce4+(aq) + Tl+(aq) --> 2 Ce3+(aq) + Tl3+(aq)

Explanation:

A non elementary reaction is a reaction that does not occur in a single reactive encounter.

Again, the rate determining step in a reaction sequence is the slowest step in the sequence. Usually, the rate law is derived from the concentration of species involved in the rate determining step as shown in the answer above.

Secondly, the overall equation is obtained by summing up all the reactants and products and cancelling out intermediate species. This leaves us with the overall balanced reaction equation as shown in the answer.

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