The local pavilion is hosting an outdoor concert. There are both lawn seats and reserved seating available. Lawn seats cost$10, while
Question:
purchased 30 seats using all of the money, how many lawn seats and how many reserved seats did the sponsoring business
purchase?
The business purchased lawn seats and reserved seats
Answers
Let the lawn seats purchased by the business be : L
Let the reserved seats purchased by the business be : R
Given :
⊕ Cost of each lawn seat : $10
⊕ Cost of each reserved seat : $25
⊕ Sponsoring business has given the $375 to purchase seats
⊕ School purchased 30 seats using all of the money
⇒ L + R = 30 (1)
⇒ 10L + 25R = 375 (2)
Multiplying equation (1) with 10, we get :
⇒ 10L + 10R = 300 (3)
Subtracting equation (3) from equation (2), we get :
⇒ 10L + 25R - (10L - 10R) = 375 - 300
⇒ 25R - 10R = 75
⇒ 15R = 75
⇒ R = 5
Substituting R = 5 in equation (1), we get :
⇒ L + 5 = 30
⇒ L = 25
The Business purchased 25 lawn seats and 5 reserved seats
1) c 2143.6 cm
2) c 113.0 m
3) a 33.5 ft
4) d 2 cm
5) c 20 mm
6) 180 in
7) d 120 ft
it's equivalent, so we can say that its equal.
let's call the denominator x and the numerador is 18 less then denominator, x - 18.
[tex]\frac{2}{5}=\frac{x-18}{x}[/tex]
multiply
2.x = 5.(x - 18)
2x = 5x - 90
90 = 5x - 2x
90 = 3x
x = 90/3
x = 30
so:
[tex]\frac{2}{5}=\frac{30-18}{30}[/tex]
[tex]\frac{2}{5}=\frac{12}{30}[/tex]
[tex]Answer this question! eric has a riddle "i am thinking of a fraction that is equivalent to 2/5 and[/tex]