The length of a rectangle is 5 units and its width is 4 units. what is the approximate length of the

Pythagorean theorem

c2 = a2 + b2
c2 = 5^2 + 4^2
c2 = 25 + 16
c2 = 41
c = 6.4

HOpe this helps

c = 6.4

Step-by-step explanation:

7.2 use the pythagorean theorem after you draw the rectangle and label the units and draw a diagonal line to find the length

The length of the diagonal is 8.6 units .

Option (C) is correct.

Step-by-step explanation:

As given

The length of a rectangle is 7 units and its width is 5 units.

Now by using the pythagorean theorem

Hypotenuse² =  Perpedicular² + Base²

Now as shown in the figure given below.

AC² = AD² + DC²

As

AD = 5 units

DC = 7 units

Put in the above

AC² = 5² + 7²

AC² = 25 + 49

AC² = 74

[tex]AC = \sqrt{74}[/tex]

AC = 8.6 units

Therefore the length of the diagonal is 8.6 units .

Option (C) is correct.

  4√5 ≈ 8.944 units

Step-by-step explanation:

The given points are on a vertical line, separated by 4 units (from y=-5 to -1). The Pythagorean theorem tells you the length of the diagonal is ...

  d² = 4² + 8² = 80

  d = √80 = 4√5 ≈ 8.944 . . . units

The length of a diagonal is 4√5, about 8.944 units.

7.2 units

Step-by-step explanation:

The diagonal of the rectangle and the length and the width of the rectangle form right triangle in which diagonal is the hypotenyse.

By the Pythagorean theorem,

[tex]\text{Hypotenuse}^2=\text{Leg}_1^2+\text{Leg}^2_2[/tex]

for this right triangle you get

[tex]\text{Diagonale}^2=\text{Length}_1^2+\text{Width}^2_2[/tex]

Since

[tex]\text{Length}=6\ units\\ \\\text{Width}=4\ units,[/tex]

then

[tex]\text{Diagonale}^2=6^2+4^2\\ \\\text{Diagonale}^2=36+16\\ \\\text{Diagonale}^2=52\\ \\\text{Diagonal}=\sqrt{52}=2\sqrt{13}\approx 7.2\ units[/tex]

b

Step-by-step explanation:

using pythagoras theorem:

d=(5^2+4^2)^1/2

=6.4 units

Just need to apply Pythagora's Theorem:

a² + b² = c²

Where a and b are the sides, and c is the diagonal, therefore:

7² + 5² = c²

49 + 25 = c²

c = √(74)

c = 8.6

8.6 units

Option A. [tex]4.3\ cm[/tex]

Step-by-step explanation:

we know that

To find the diagonal of the rectangle apply the Pythagoras Theorem

Let

D-----> the diagonal of rectangle

L----> the length of rectangle

W---> the width of rectangle

so

[tex]D^{2}=L^{2}+W^{2}[/tex]

substitute the values

[tex]D^{2}=3.6^{2}+2.4^{2}[/tex]

[tex]D^{2}=18.72[/tex]

[tex]D=4.3\ cm[/tex]

The answer i-

D - 7.2 units.