The length of a rectangle is 5/6 feet. the width is 3/8 feet. how much greater is the length of the

5 answers
Question:

The length of a rectangle is 5/6 feet. the width is 3/8 feet. how much greater is the length of the rectangle than the width?

Answers

5/6 of a foot is 25.4 centimeters and 3/8 of a foot is 11.43 centimeters. To find how much greater than 5/6 is, you subtract. The difference is 13.97. So 5/6 of a foot is 13.97 centimeters larger than 3/8 of a foot.

0.46 feet

Step-by-step explanation:

Length = 5/6 feet (or 0.254 m)

Width = 3/8 feet (or 0.114 m)

(5/6 - 3/8) feet = 11/24 feet or 0.46 feet (0.140 m)

C 11/24 ft

Step-by-step explanation:

5/6ft, and 3/8ft LCM (Least common multiple) would be 24 so what you do to the dominator u do to the numerator so 5/6ft × 4 = 20/24ft

and 3/8ft × 3 = 9/24ft

Final step: 20/24ft - 9/24ft = 11/24ft

C) 11/24

Step-by-step explanation:

rewrite each fraction as equivalent fraction with common denominator.

LCM(6,8) is 24

5/6 = 20/24

3/8 = 9/24

The difference between 20/24 and 9/24 is 11/24

The way you figure this out is by taking the length (5/6) and subtracting the width (3/8). in order to subtract fractions, they need a common denominator. the number 24 works well for this as 8*3=24 and 6*4=24. in order to keep everything equivalent, we can only multiply by 1, but we can rewrite 1 by taking a number over itself, such as 3/3 and 4/4.
 
so if we take 5/6 and multiply by 4/4 (which is still equal to 1) we get 20/24.  

next we multiply 3/8 by 3/3 (which is still equal to 1) we get 9/24. 

now that we have a common denominator, we can simply subtract them. 20/24-9/24=11/24

this means our answer is C. 11/24 ft

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