The Height H(t) (in feet) of a projectile fired vertically into the air from the ground is given by the equation H(T) = -16t^2 + 96t, where t is time

a) 3s

B) 144m

C) 6s

Step-by-step explanation:

Given the height modeled by the function;

H(T) = -16t^2 + 96t,

The body will reach its maximum height when dh/dt = 0 (when velocity is zero)

dh/dt = -32t + 96

0 = -32t + 96

32t = 96

t = 96/32

t = 3s

Hence it will take the projectile 3s to reach its maximum height'

B) To get the maximum height we will substitute t = 3 into the equation

H(T) = -16t^2 + 96t,

H(3) = -16(3)^2 + 96(3)

H(3) = -144+ 288

H(3) = 144m]

Hence the maximum height is 144m

C) The projectile reaches the ground at h = 0

H(T) = -16t^2 + 96t,

0= -16t^2 + 96t,

16t² = 96t

16t = 96

t = 96/16

t = 6

Hence it will take the projectile 6s to reach the ground again

It seems like a lot of movies

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