# The function c(x) = 29x + 54.5 represents the cost (in dollars) of cable for x months, including the

###### Question:

a. how much would you have spent on cable after 6 months?

## Answers

$ 228.50

Step-by-step explanation:

C(x) = 29x + 54.50

C(6) = 29(6) + 54.50

C(6) = 174+ 54.50

C(6) = 228.50

a. [tex]\$228.5[/tex]

b. 10 months.

Step-by-step explanation:

a. Given the function the following function:

[tex]C(x) = 29x + 54.5[/tex]

You can calculate the amount of money (in dollars) you would spent on cable after 6 months through this procedure:

- Substitute [tex]x=6[/tex] into the function:

[tex]C(6) = 29(6) + 54.5[/tex]

- Evaluating, you get:

[tex]C(6) =228.5[/tex]

b. The steps to calculate the number of months of cable service that you can you have for $344.50, are:

- Rewrite the function in this form:

[tex]y = 29x + 54.5[/tex]

- Substitute [tex]y=344.50[/tex] into the function and then solve for "x":

[tex]344.50= 29x + 54.5\\\\290=29x\\\\\frac{290}{29}=x\\\\x=10[/tex]

a. [tex]\$228.5[/tex]

b. 10 months.

Step-by-step explanation:

a. Given the function the following function:

[tex]C(x) = 29x + 54.5[/tex]

You can calculate the amount of money (in dollars) you would spent on cable after 6 months through this procedure:

- Substitute [tex]x=6[/tex] into the function:

[tex]C(6) = 29(6) + 54.5[/tex]

- Evaluating, you get:

[tex]C(6) =228.5[/tex]

b. The steps to calculate the number of months of cable service that you can you have for $344.50, are:

- Rewrite the function in this form:

[tex]y = 29x + 54.5[/tex]

- Substitute [tex]y=344.50[/tex] into the function and then solve for "x":

[tex]344.50= 29x + 54.5\\\\290=29x\\\\\frac{290}{29}=x\\\\x=10[/tex]