The figure below shows a right triangle: A right triangle is shown with hypotenuse equal to q units

C

Step-by-step explanation:

Let's calculate each option.

A: tan y = opposite / adjacent = r / p

b: sin x = opposite / hypotenuse = p / q

c: sin y = opposite / hypotenuse = r / q

d: tan x = opposite / adjacent = p / r

Hey there! :)

C. sin y°

Step-by-step explanation:

In the diagram, q represents the hypotenuse. We can begin by eliminating A and D because they consist of the tangent. (opp/adj)

Let's look at choices B and C.

B) sin x°. The sine of x is equal to opposite/hypotenuse, which in this instance equals p/q. This is incorrect, because we are looking for which trigonometric ratio equals r / q.

C). sin y°. The sine of y equals r /q, which is makes this choice correct.

(a)tanx

step-by-step explanation:

it is given that there is a right triangle with hypotenuse equal to q units and the length of the legs equal to p units and r units.  

we know that , and then, from the given figure, we have

p is the perpendicular and r is the base of the given triangle, then

thus, option a is correct.

, [tex]siny = \frac{r}{q}[/tex] . Correct option D) sin y° .

Step-by-step explanation:

Here we have , The figure below shows a right triangle: A right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units. The angle b . We need to find What is r ÷ q equal to . Let's find out :

We have the following dimensions for the right angle triangle as

[tex]Perpendicular =p\\Base=r\\Hypotenuse=q[/tex]

Now, [tex]\frac{r}{q} = \frac{Perpendicular}{Hypotenuse}[/tex]    ..........(1)

but , [tex]siny = \frac{Perpendicular}{Hypotenuse}[/tex]  ...........(2)

Putting value of equation (1) in equation (2) we get:

⇒ [tex]siny = \frac{Perpendicular}{Hypotenuse}[/tex]

⇒ [tex]siny = \frac{r}{q}[/tex]

Therefore , [tex]siny = \frac{r}{q}[/tex] . Correct option D) sin y° .

Correct option D) sin y° .

Step-by-step explanation:

Here we have , The figure below shows a right triangle: A right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units. The angle b . We need to find What is r ÷ q equal to . Let's find out :

We have the following dimensions for the right angle triangle as

Now,     (1)

but ,   (2)

Putting value of equation (1) in equation (2) we get:

⇒

⇒

Therefore ,  . Correct option D) sin y° .

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

[tex]\tan\left(x\right)=\frac{\left[altitude\right]}{\left[base\right]}=\frac{p}{r}[/tex]

[tex]\tan\left(x\right)=\frac{p}{r}[/tex]

[tex]\frac{p}{r}=tan(x)[/tex]

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

tan x° = p/r

Step-by-step explanation:

Hypotenuse = q

The other 2 legs are p and r.

The angle between p and r is y°, which is opposite to that of the hypotenuse.

The angle between r and q is x°.

p is the opposite side and r is the adjacent side of angle x.

So, tan x° = opp / adjacent = p/r

Hmm
if o=length of side oposite angle
and a=lenght of side adjacent angle
and h=length of hypotnuse then

sin=o/h
cos=a/h
tan=o/a

so p/r must be tan of something
tan=oposite side/adjacen side
r is the adjaent side
and p is oposite
so it must be angle x

so it is tan (x)


first option is correct