The environmental protection agency is attempting to revive 3 acres of contaminated soil

346 trucks are needed

Step-by-step explanation:

We know that one acre equals 43560 feet ^ 2

In this case the area is 3 acres. So:

[tex]3\ acres * \frac{43,560\ ft^2}{1\ acre} = 130,680\ ft^2[/tex]

We know that 1 foot equals 12 inches. So:

[tex]24\ in * \frac{1\ ft}{12\ in} = 2\ ft[/tex]

So the volume of the contaminated area is:

[tex]V = 2* 130,680\ ft^3\\\\V = 261,360\ ft^3[/tex]

In a cubic yard there are 27 cubic feet. So:

[tex]28\ yard^2 * \frac{27\ ft^3}{1\ yard^3} = 756\ ft^3[/tex]

Finally if we have a volume of [tex]261,360\ ft ^ 3[/tex] and each truck can transport [tex]756\ ft ^ 3[/tex] then the amount of trucks x we need is:

[tex]x = \frac{261,360\ ft ^ 3}{756\ ft ^ 3} = 346\ trucks[/tex]

[tex]346\ trucks[/tex]

Step-by-step explanation:

1 acre equals to 4840 yard²

So

[tex]3\ acres *\frac{4840\ yard^2}{1\ acre}= 14520\ yard^2[/tex]

Also

[tex]1\ in = 0.02778\ yard[/tex]

So

[tex]24\ in *\frac{0.02778\ yard}{1\ in}= 0.667\ yard[/tex]

So volume V of the contaminated area is:

[tex]V = 14520*0.667\ yard^3\\\\V=9680.48\ yard^3[/tex]

If each truck has a capacity of 28 cubic yards then it is necessary

[tex]9680.48\ yard^3 * \frac{1\ truck}{28\ yard^3}=346\ trucks[/tex]

step-by-step explanation:

so then what are you asking?

step-by-step explanation: