Tell whether the equation has one, zero, or infinitely many solutions.8(x-4) + 19 = 8x - 13

10 answers
Question:

Tell whether the equation has one, zero, or infinitely many solutions.
8(x-4) + 19 = 8x - 13

Answers

6+3x=x-8  subtract 6 from both sides

3x=x-14  subtract x from both sides

2x=-14  divide both sides by 2

x=-7

This equation thus has just one solution.

no solutions

Step-by-step explanation:

i hope this helps

none

Step-by-step explanation:

6x-1=6x-1 infintely many

4x-8=4x+10 no solution

4x+5=4x+15 no sloution

4n-7=5n+1 n=-8

-8x+52=-26-32x 24x=78 x= 3 1/4

8y+32=7y+38  y=6

Hope this helps your spelling/typing is a bit off but mark brainliest :D

some of them are wrong bcuz i dont know the real typing :(

infinitely many solutions

distribute right side of equation

8x + 4 = 8x + 4

since both sides are equal then any value of x is a solution

infinitely many solutions

Step-by-step explanation:

When solving equations, three different answers are possible:  one, none or infinite solutions.  When an equation has one solution, the value of the variable can be only one answer, for example:

x - 2 = 6  or x = 8

When an equation has no solution, then the value of the variable can not be solved, for example:

x + 2 = x - 2  or 2 = -2, which is not possible

When an equation has infinite solutions, then the value of the variable can be all real numbers, for example:

3y - 6 = 3y - 6 or 0 = 0, infinite solutions

Infinitely many

Step-by-step explanation:

The answer to the question
[tex]Tell whether each equation has one ,zero,or infinitely many solutions 1: 5(x-3)+6=5x-9 2: 5(x-3)+6[/tex]

Yup here you go it’s uh idk anymore heheh

−(8x + 1) − 3 = −7x − (x + 4)
-8x - 1 - 3 = -7x - x - 4
-8x - 4 = -8x - 4
0 = 0

answer
infinitely many solutions.

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