# Suppose that Ayumi rolls a pair of fair six-sided dice. Let A be the event that the first die lands

###### Question:

1/6 1/6 1/36 independent

I got tired of waiting but if you want the points for the questions have at it

## Answers

[tex]\frac{1}{6} ,\frac{1}{6} ,\frac{1}{36}\,,\,independent[/tex]

Step-by-step explanation:

Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.

To find:

P(A), the probability that the first die lands on 2

P(B), the probability that the second die lands on 2

P(A and B): the probability that the first die lands on 2 and the second die lands on 2

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Sample space = [tex]\left \{ 1,2,3,4,5,6 \right \}[/tex]

Total number of outcomes = 6

For P(A):

Number of favourable outcomes = 1

So,

[tex]P(A)=\frac{1}{6}[/tex]

For P(B):

Number of favourable outcomes = 1

So,

[tex]P(B)=\frac{1}{6}[/tex]

P(A and B) = [tex]P(A)P(B)=\left ( \frac{1}{6} \right )\left ( \frac{1}{6} \right )=\frac{1}{36}[/tex]

Yes, A and B are independent events as happening of each of the event does not depend on the other.

answer: answer

step-by-step explanation:

answer:

write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.