Suppose 100 ml of hydrochloric acid is neutralized by exactly 46.9ml of 0.75M lithuim hydroxide . What is the concentration

3 answers
Question:

Suppose 100 ml of hydrochloric acid is neutralized by exactly 46.9ml of 0.75M lithuim hydroxide . What is the concentration of the hydrochloric acid?

Answers

0.0035M

Explanation:

Given parameters

Volume of HCl  = 100mL  = 0.1L

Volume of LiOH = 46.9mL  = 0.0469L

Molarity of LiOH = 0.75M

Unknown:

Concentration of hydrochloric acid = ?

Solution:

The reaction equation is given as;

         HCl   +  LiOH →   LiCl  + H₂O

Let us find the number of moles of the given specie which is LiOH;

   Number of moles  = molarity x volume;

    Number of moles of LiOH = 0.75 x0.0469  = 0.035moles

From the balanced reaction equation;

        1 mole of LiOH combines with 1 mole of HCl

     0.035mole of LiOH will require 0.035mole of HCl

Concentration of HCl = [tex]\frac{number of moles of HCl}{volume of HCl}[/tex]  

 Concentration of HCl  = [tex]\frac{0.035}{0.1}[/tex]   = 0.0035M

 

The answer would be

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