Question 3 (5 points) the length of a rectangular poster is 10 inches longer than the width. if the

width = 26 inches

Step-by-step explanation:

perimeter of a rectangle= p

p= 2*L+ 2*w

L= length

w= width

The statement tell us:

L= 10+w

p=124

124=2*(10+w) +2*w

124= 20+2w+2w

124-20=4w

w=104/4

w=26 =width

The formula for the perimeter is 2L + 2W.

Since we know that L=10+W, we can substitute this into the equation.

2(10+W) +2W=124

20+2W + 2W=124

4W +20 = 124

4W=104

W=26

Therefore, the width is 26 inches.

So basically I let length = w + 10
perimeter = 124

therefore, w+w+w+10+w+10 = 124
will give you, 4w + 20 = 124
then subtract, 4w = 124 - 20
then divide, w = 104/ 4
results,. w = 26 inches.

in conclusion, width = 26inches and
length = 26 + 10 = 36inches.

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You divide 124 to 10 and your width would be 12.4