Question 10 an urn contains two white marbles and one black marble. a marble is drawn from the urn without
2 answers
Question:
Question 10 an urn contains two white marbles and one black marble. a marble is drawn from the urn without replacement and put aside without my seeing it. then a second marble is drawn, and it is white. what is the probability that the unknown removed marble is white, and what is the probability that it is black?
Answers
2 whites and 1 black = 3 marbles
P(white + white) = (2/3)(1/2) = 2/6 = 1/3
P(white + black) = (2/3) (1/2) = 2/6 = 1/3
Ans: (a) 1/3 (b) 1/3
Step-by-step explanation:
No. Of white marble n(W) = 2
No. Of black marble n(B) = 1
Total no. Of marble N = 2 + 1 = 3
Prob(1st is white) = n(W)/N = 2/3
Prob(1st is black) = n(B)/N = 1/3
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