# Priya writes the equation y = -1/2x - 7. Write an equation that has:1. exactly one solution in common

###### Question:

2. no solutions in common with Priya's equation

3. infinitely many solutions in common with Priya's equation, but looks different than hers

## Answers

Answer and Explanation:

According to the scenario, computation of the given data are as follow:-

a. At The End of Period Outstanding Shares = Issue Share + Beginning Shares + Resold Share - Repurchase Share

= 1,200 + 2,400 + 50 - 230

= 3,420 Shares

B) Issued Shares = Issued Shares + Beginning Shares

= 1,200 + 2,400

= 3,600 Shares

c. The c part is shown in the excel spreadsheet kindly find it below.

d). Balance Sheet

Particular Amount ($)

Common stock$25,200

PIC in excess of treasury stock$50

PIC in excess of common stock$38,300

Retained earnings$74,600

Less-treasury stock-$4,680

Total equity of stockholder$133,470

[tex]The following information pertains to JAE Corp. at January 1, 2018: Common stock, $11 par, 12,000 s[/tex]

[tex]The following information pertains to JAE Corp. at January 1, 2018: Common stock, $11 par, 12,000 s[/tex]

b

Step-by-step explanation:

u

can we be friends i don't have any.

He is correct.

Step-by-step explanation:

Because a linear system in three variables means that they have solutions if the all three have points in common in R3 space. But, in the case that they don't have any solution mean the opposite, they don't have points in common in R3 space.

In a linear system, variables must be related through common points. So, graphically, you should draw intersecting geometrical places in order to show the intersections, wich are the common results or points that are the solutions of the linear system.

I used the part to whole way.

60%is equal to 60 over 100, or 6 over 10.

6 is the part. 10 is the whole.

In the same way, 48 is the part, but you need to find the whole.

6 times 8 is 48.

Now, you can multiply 10 times 8 to find the whole.

10 time 8 is 80.

80 is the answer.

The molecular equation is

AgNO3(aq]+HCl(aq]→AgCl(s]+HNO3(aq]

How did I get this equation? Consider each reactant or product separately:

1 mole of AgNO3 contains 1 mole of Ag+ and 1 mole of NO−3 ions.

Ag+(aq]+NO−3(aq]+H+(aq]+Cl−(aq]→AgCl(s]⏐⏐↓+H+(aq]+NO−3(aq]

The net ionic equation is

Ag+(aq]+Cl−(aq]→AgCl(s]⏐⏐↓

Now try some of the others on your own

In a) the final equation is AgNO3 + KCl = AgCl + KNO3, b) Ni(NO3)2 + Na2S = 2NaNO3 + NiS; c) CaCl2 + Na2CO3 = 2 NaCl + CaCO3. In 2) The total net equation is Ca 2+ + CO32- = CaCO3 (s).

Person above me is correct :)