Pls, read both questions. I need help real quick
Question:
[tex]Pls, read both questions. I need help real quick[/tex]
[tex]Pls, read both questions. I need help real quick[/tex]
Answers
1:120 2: 36
Step-by-step explanation:
1: The interior angle of a hexagon is 4*180/6=120. Double that, and we get 240. x is 360-240=120.
2: The interior angle of a pentagon is 108, 180-108=72, 72/2=36=x
2
Step-by-step explanation:
solve for x (make x on one side and bring all numbers to other side)
multiply 5 into parenthesis
5x+15=25
subtract both side 15
5x=10
divide 5 both side
x=2
[tex]\boxed {\tt 13.75 \ yards}[/tex]
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean Theorem.
[tex]a^2+b^2=c^2[/tex]
where [tex]a[/tex] and [tex]b[/tex] are the legs and [tex]c[/tex] is the hypotenuse.
One of the legs is 10 yards, and the other is unknown. The hypotenuse is 17 yards, because it is the longest side.
[tex]a= 10 \ yd\\b=b\\c= 17 \ yd[/tex]
Substitute the values into the formula.
[tex](10 \ yd)^2+b^2=(17 \ yd)^2[/tex]
Evaluate the exponents.
(10 yd)²= 10 yd * 10 yd = 100 yd²[tex]100 \ yd^2+b^2= (17 \ yd)^2[/tex]
(17 yd)²= 17 yd * 17 yd=289 yd²[tex]100 \ yd^2+b^2= 289 \ yd^2[/tex]
Now, solve for b. First, subtract 100 yards squared from both sides of the equation.
[tex]100 \ yd^2-100 \ yd^2+b^2= 289 \ yd^2- 100 \ yd^2[/tex]
[tex]b^2=289\ yd^2-100 \ yd^2[/tex]
[tex]b^2=189 \ yd^2[/tex]
Finally, take the square root of each side of the equation.
[tex]\sqrt{b^2} =\sqrt{189\ yd^2}[/tex]
[tex]b=\sqrt{189 \ yd^2}[/tex]
[tex]b=13.7477271 \ yd[/tex]
Round to the nearest hundredth. The 7 in the thousandth place tells us to round the 4 to a 5.
[tex]b \approx 13.75 \ yd[/tex]
The other side of the garden is about 13.75 yards long.
a d c d
Explanation:
B is one of them
Step-by-step explanation:
Is this Khan Academy?
Step-by-step explanation:
4c = d
c = d/4
The length of image of AB after the dilation is 18 cm
Solution:
Given data:
Length of AB = 9 cm
Scale factor (k) = 2
Length of image of AB = ?
By the definition of scale factor,
[tex]$k=\frac{\text { Length of Dilated image AB }}{\text { Length of original image } \mathrm{AB}}$[/tex]
[tex]$2=\frac{\text { Length of Dilated image AB }}{9}[/tex]
Do cross multiplication, we get
2 × 9 = Length of dilated image of AB
18 = Length of dilated image of AB
Hence the length of image of AB after the dilation is 18 cm.
X = 2
Step-by-step explanation:
5(x+3) = 25
25 / 5 = 5
x + 3 = 5
5 - 3 = x
x = 2
A,d,c,d
That’s what I think it it
B is the answer because I had this problem