Please help addison shes having iusses finding Zed its not your fault trust me addi

shwaty the baddest

Explanation:

im helping

Explanation:

                                       Question 5)

Given the points

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(2,\:0\right),\:\left(x_2,\:y_2\right)=\left(5,\:5\right)[/tex]

[tex]m=\frac{5-0}{5-2}[/tex]

[tex]m=\frac{5}{3}[/tex]

Therefore, the slope is:

[tex]m=\frac{5}{3}[/tex]

                                          Question 6)

Given the points

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(-1,\:0\right),\:\left(x_2,\:y_2\right)=\left(-2,\:3\right)[/tex]

[tex]m=\frac{3-0}{-2-\left(-1\right)}[/tex]

[tex]m=-3[/tex]

Therefore, the slope is:

[tex]m=-3[/tex]

                                       Question 7)

Given the points

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(-1,\:-1\right),\:\left(x_2,\:y_2\right)=\left(1,\:3\right)[/tex]

[tex]m=\frac{3-\left(-1\right)}{1-\left(-1\right)}[/tex]

[tex]m=2[/tex]

Therefore, the slope is:

[tex]m=2[/tex]

                                         Question 8)

Given the points

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(2,\:0\right),\:\left(x_2,\:y_2\right)=\left(-2,\:4\right)[/tex]

[tex]m=\frac{4-0}{-2-2}[/tex]

[tex]m=-1[/tex]

Therefore, the slope is:

[tex]m=-1[/tex]

                                     Question 9)

Given the points

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(0,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:-2\right)[/tex]

[tex]m=\frac{-2-1}{4-0}[/tex]

[tex]m=-\frac{3}{4}[/tex]

Therefore, the slope is:

[tex]m=-\frac{3}{4}[/tex]

                                        Question 10)

Given the points

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(0,\:2\right),\:\left(x_2,\:y_2\right)=\left(1,\:-3\right)[/tex]

[tex]m=\frac{-3-2}{1-0}[/tex]

[tex]m=-5[/tex]

Therefore, the slope is:

[tex]m=-5[/tex]

Given

distributive property

Subtraction property of equality

Addition property of equality

Division property of equality

Solution

Step-by-step explanation:

I DONT GET IT AND IS THAT U IN YO PROFILE PIC LOL

Step-by-step explanation:

I got B) ; 54m2

Step-by-step explanation:

the above diagram is a trapezium.

the area is gotten by; 1/2 (a+b)h

a = shortest side.

b = the longer side that is directly opposite to (a).

h = height.

1/2(3 + 9)9

1/2 by 12 by 9

to get 54

I think it is BCD but you might want to get someone else to check it it has been a long time sense i have done that

Step-by-step explanation:

Is there a picture to show the problem??

Step-by-step explanation:

The lateral surface area of the rectangular pyramid is equal to sum of area of 4 lateral triangles.

Here, the base is square, then 4 lateral triangles have equal area.

=> Lateral surface area of this rectangular pyramid:

A = (area of lateral triangle) x 4

  = (12 x 14 x 1/2) x 4 = 336 (ft2)

=> Option C is correct.

Hope this helps!

:)

x = 31

Step-by-step explanation:

The sum of the internal angles = 180°

then:

2x-5 + x+10 + 2x+20 = 180

5x + 25 = 180

5x = 180 - 25

5x = 155

x = 155/5

x = 31

Check:

2*31 - 5   +  31+10   +  2*31 + 20  = 180

62-5  +   41   +  62+20 = 180

57 + 41 + 82 = 180