Plane 1 leaves city a at 7 am and flies at a speed of 250 mph in a straight line towards city b, located

3 answers
Question:

Plane 1 leaves city a at 7 am and flies at a speed of 250 mph in a straight line towards city b, located 1000 miles north of city a. plane 2 leaves city c located 300 miles east and 400 miles north of city a at 7: 30 am and flies west at a speed v mph. the planes fly at the same altitude. for which value of v do they collide ?

Answers

v=142.85 mph

Explanation:

Given

Distance between two cities is 1000 miles

Speed of plane 1 id 250 mph

Plane 1 leaves at 7 am and Plane 2 leaves at 7:30 am

They will collide if plane 2 travels 300 miles and Plane  1 travels 400 miles in t and t+0.5 hr  respectively

Time taken by plane 2

[tex]t=\frac{300}{v}[/tex]----1

time taken by plane  1 to travel 400 miles

[tex]t+0.5=\frac{400}{250}[/tex]-----2

substitute value of t in 2

[tex]\frac{300}{v}+0.5=\frac{400}{250}[/tex]

[tex]\frac{300}{v}=2.1[/tex]

[tex]v=\frac{300}{2.1}=142.85 mph[/tex]

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