3 answers
Question:

Consider the equilibrium system described by the chemical reaction below. Calculate the value of Qc for the initial set reaction conditions in a 1.50 L container: 0.00623 mol H₂, 0.00414 mol I₂, 0.0244 mol HI.\

Answers

This is an incomplete question, here is a complete question.

Consider the equilibrium system described by the chemical reaction below. Calculate the value of Qc for the initial set reaction conditions in a 1.50 L container: 0.00623 mol H₂, 0.00414 mol I₂, 0.0244 mol HI.

[tex]2HI(g)\rightleftharpoons H_2(g)+I_2(g)[/tex]

Answer : The value of [tex]Q_c[/tex] is, 0.00431

Explanation :

Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

[tex]2HI(g)\rightleftharpoons H_2(g)+I_2(g)[/tex]

The expression for reaction quotient will be :

[tex]Q_c=\frac{[H_2][I_2]}{[HI]^2}[/tex]

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

First we have to calculate the concentration of [tex]HI,H_2\text{ and }I_2[/tex]

[tex]\text{Concentration of }HI=\frac{\text{Moles of }HI}{\text{Volume of solution}}=\frac{0.0244mol}{1.50L}=0.0163M[/tex]

[tex]\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.00623mol}{1.50L}=0.00415M[/tex]

[tex]\text{Concentration of }I_2=\frac{\text{Moles of }I_2}{\text{Volume of solution}}=\frac{0.00414mol}{1.50L}=0.000276M[/tex]

Now put all the given values in this expression, we get

[tex]Q_c=\frac{(0.00415)\times (0.000276)}{(0.0163)^2}[/tex]

[tex]Q_c=0.00431[/tex]

Therefore, the value of [tex]Q_c[/tex] is, 0.00431

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