Question:
The parabola has a vertex at
O,
Answers
6mm^3 or .6cm^3
216
/ \
36 6
/ \ /
6 6 6
factor trees are nice.
isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?
a^2 + b^2 = c^2
let c = distance from starting point.
(3)^2 + (5)^2 = c^2
9 + 25 = c^2
34 = c^2
sqrt{34} = sqrt{c^2}
sqrt{34} = c
answer: the correct option is d.
explanation:
it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.
from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then
[tex]k=\frac{ok'}{ok}[/tex] (1)
distance formula,
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]ok'=\sqrt{(2-0)^2+(4-0)^2}= \sqrt{4+16}= \sqrt{20}=2\sqrt{5}[/tex]
[tex]ok=\sqrt{(4-0)^2+(8-0)^2}= \sqrt{16+64}= \sqrt{80}=4\sqrt{5}[/tex]
put these values in equation (1).
[tex]k=\frac{2\sqrt{5}}{4\sqrt{5}}= \frac{1}{2}[/tex]
therefore scale factor is [tex]\frac{1}{2}[/tex] and option d is correct.
the five is the numerator
[tex]Why is the five in the cushion written above the 9 in the dividend? what does the 5 mean in the quo[/tex]