Moremath!MixedReviewFISEincorrectPOINTSTODAYPOINTSGAMETHIS WEEK CREDITSPOINTSREMAININGA.

he set the factored expressions equal to each other.

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Step-by-step explanation:

f(x) = x² + 4x + 3

The function intercepts x when y = 0, so, just make the function equals 0

f(x) = 0 = x² + 4x + 3

So, x² + 4x + 3 = 0 and if we factor, x² + 4x + 3 = (x + 3).(x + 1) = 0

And with factoring we know that x intercepts in -3 and -1

He set the factored expressions equal to each other.  instead of setting them equal to zero

Step-by-step explanation:

f(x) = x^2 + 4x + 3. His work is shown below.

0 = x^2 + 4x + 3

0 = (x + 3)(x + 1)

Here is where we use the zero product property

x+3 = 0   x+1 =0  We do not set them equal to each other

He set the factored expressions equal to each other

Step-by-step explanation:

Step-by-step explanation:

He set the factored expressions equal to eachother

X intercepts are points where a function intersects or cuts through the x axis where y=0.

Step-by-step explanation:

In the function given which is f(x) =x^2 +4x + 3 we see that this is a parabola of which when the graph is drawn it has a U shape so when finding x intercepts of this function it is those points on the function where the graph cuts the x axis and at those two points f(x)= 0, so here Mathieu had made a mistake of factorizing and equating the x intercepts for this function.

For finding the X intercepts let f(x) = 0

therefore 0= x^2 + 4x + 3  now we solve for x

0= (x+1)(x+3)  

(x+1)= 0 or (x+3)=0

therefore x=-1 or x=-3

now if you substitute these values onto the function they give f(x)= 0,

f(-1) = (-1)^2 + 4(-1) + 3 = 0

f(-3) = (-3)^2 + $(-3) + 3 =0

now let us look at Mathieus answer which is x+1 = x+3 yes these x values do give the same y value but they are not equal because if you can actually solve this further you would not get a defined answer. Both these are factors of the function but are not actually equal as the function would not be able to be drawn if this was the case.

He got 16 questions right (5x16=80) and 10 wrong (8x10=80) He got paid $80 but also had to pay $80. 

If [tex]\frac{6}{7}[/tex] were incorrect, it means that [tex]\frac{1}{7}=4[/tex] were correct
[tex]4*7=28[/tex]
There were 28 problems ;)

If [tex]\frac{6}{7}[/tex] were incorrect, it means that [tex]\frac{1}{7}=4[/tex] were correct
[tex]4*7=28[/tex]
There were 28 problems ;)