Model each problem with a quadratic equation. then solve. if necessary, round to the nearest tenth1. find the side length of a square with an area

1.26cm that the answer

[tex]8\pi 

 is the correct solution to your problem[/tex]

9.87

Step-by-step explanation:

the formula is A=π r^2

A stands for Area

π  stands for pi (3.14159...)

r stands for radius

^2 stands for (to the power of 2)

[tex]Area = pi * r^{2} \\5 = 3.142 * r^{2} \\r^{2} = 5 / 3.142\\r^{2} = 1.59\\r = \sqrt{1.59} \\r = 1.26cm[/tex]

Hello! radius is 6

Step-by-step explanation:

It shows that the diameter is 12 the radius is half of that therefore the radius is 6 hope that helps!

r= 8

Step-by-step explanation:

c= 2r

c=2× 8= 16 plz mark it as brainlist thank u!!

r=12

Step-by-step explanation:

The formula for the circumference of a circle is C = 2r, where r is the radius and C is the circumference. The equation solved for r is r = r equals StartFraction C Over 2 pi EndFraction..

Find the radius of a circle that has a circumference of 16.

r = 4

r = 8

r = 12

r = 16

Step-by-step explanation:

The radius is half the size of the diameter. So, we will divide 60 by 2 in order to get the radius.

60 ÷ 2 = 30

So, the radius of the circle is 30 mm

The answer is B

Step-by-step explanation:

r = c/2π

c = 16π

r = 16π/2π

= 8

The Radius of circle is 7.15 cm  

Step-by-step explanation:

Given as :

A Triangle is inscribed into circle

The center of circle is O

The Diameter of circle = AK = d

The hypotenuse of triangle being the diameter of circle

The Area of triangle = 50 cm²

Let The radius of circle = r cm

The Triangle is right angle at c

So , ∠ACK = 90°

∠CAK = 42°

∠AKC = 180° - (90° + 42°)

So, ∠AKC = 48°

Now, ∵ Area of triangle ACK = 50 cm²

So, [tex]\dfrac{1}{2}[/tex] × AC × CK = 50

Or, AC × CK = 50 × 2

i.e , AC × CK = 100        ..........1

From figure

Sin 48° =  [tex]\dfrac{AC}{AK}[/tex]

Or, 0.74 =  [tex]\dfrac{AC}{d}[/tex]

∴ AC = 0.74 d             ..........2

Similarly

Sin 42° =  [tex]\dfrac{CK}{AK}[/tex]

Or, 0.66 =  [tex]\dfrac{CK}{d}[/tex]

∴ CK = 0.66 d               .............3

Putting eq 2 and 3 value into eq 1

i.e  AC × CK = 100  

Or, 0.74 d  × 0.66 d = 100  

Or, 0.4884 × d² = 100  

∴ d² = [tex]\dfrac{100}{0.4884}[/tex]

Or, d² = 204.75

Or, d = [tex]\sqrt{204.75}[/tex]

Or, d = 14.30

So, The diameter of circle = d = 14.30 cm

Now, Radius of circle = [tex]\dfrac{\textrm diameter}{2}[/tex]

Or, r =  [tex]\dfrac{\textrm 14.30 cm}{2}[/tex]

i.e r = 7.15 cm

So, The Radius of circle =  r = 7.15 cm

Hence, The Radius of circle is 7.15 cm  Answer

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to [tex]\frac{1}{60} hr\\[/tex]

then mult. both sides by 75 we get the ratio

75 mi. to [tex]\frac{75}{60} hr\\[/tex]

simplifying we get

75 mi. to [tex]\frac{5}{4} hr[/tex]

or 1.25 hr.

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.